js截取url中参数值
有个url如下:
http://passport.csdn.net/account/login?from=http%3a%2f%2fwrite.blog.csdn.net%2fpostedit
我们该如何获取from这个参数的值呢?在网上搜了下方法很简单,如下,第一种是通过正则,第二种通过切串放进数组的方式:
方式一:
function getQueryString(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); var r = window.location.search.substr(1).match(reg); if (r != null) return unescape(r[2]); return null; } console.log( getQueryString("aaa") );
方式二:
1 function GetRequest() { 2 var url = location.search; //获取url中"?"符后的字串 3 var theRequest = new Object(); 4 if (url.indexOf("?") != -1) { 5 var str = url.substr(1); 6 strs = str.split("&"); 7 for(var i = 0; i < strs.length; i ++) { 8 theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); 9 } 10 } 11 return theRequest; 12 } 13 var req = GetRequest(); 14 var from = req['from']; 15 console.log(from);
参考文档:https://blog.csdn.net/tjcyjd/article/details/44275531