含有动态未知字段的 JSON 反序列化
一般来说,正常的 json 长这个模样:
{ 'Name': 'Bad Boys', 'ReleaseDate': '1995-4-7T00:00:00', 'Genres': [ 'Action', 'Comedy' ] }
这个时候我们只需要建立对应的类,直接反序列化就行(比如宇宙第一VS的 “编辑” -- “选择性粘贴” -- “将JSON粘贴为类”)
public class Movie { public string Name { get; set; } public string ReleaseDate { get; set; } public string[] Genres { get; set; } } Movie m = JsonConvert.DeserializeObject<Movie>(json);
不过有的时候会有些不负责任的 JSON
有时候它长这样:
{ "mapping": [{ "PHARMACOLOGY": "TU", "NEUROSCIENCES": "RU" }] }
有时候它还长这样:
{ "mapping": [{ "TELECOMMUNICATIONS": "YE" }] }
这个时候序列化我们就需要 字典 (Dictionary)
这个时候我们的类要长这样:
public class Rootobject { public List<Dictionary<string, string>> mapping { get; set; } }
然后照常反序列化:
Rootobject root = JsonConvert.DeserializeObject<Rootobject>(JSON);
循环下输出结果:
i++; foreach (var temp in root.mapping[0]) { Console.WriteLine(String.Format("Number:{0},Keys:{1},Values:{2}", i, temp.Key, temp.Value)); }
结果如下:
如果更麻烦一点的呢?
比如我在 https://blog.csdn.net/jdsjlzx/article/details/76785239 看到的这个json:
{ "resultcode": "200", "reason": "successed!", "result": { "sk": { "temp": "24", "wind_direction": "东北风", "wind_strength": "2级", "humidity": "28%", "time": "17:38" }, "today": { "temperature": "15℃~26℃", "weather": "多云转晴", "wind": "东北风微风", "week": "星期日", "city": "桂林", "date_y": "2015年10月11日", "dressing_index": "舒适", "dressing_advice": "建议着长袖T恤、衬衫加单裤等服装。年老体弱者宜着针织长袖衬衫、马甲和长裤。", "uv_index": "弱", "comfort_index": "", "wash_index": "较适宜", "travel_index": "较适宜", "exercise_index": "较适宜", "drying_index": "" }, "future": { "day_20151011": { "temperature": "15℃~26℃", "weather": "多云转晴", "wind": "东北风微风", "week": "星期日", "date": "20151011" }, "day_20151012": { "temperature": "16℃~27℃", "weather": "晴转多云", "wind": "微风", "week": "星期一", "date": "20151012" }, "day_20151013": { "temperature": "16℃~26℃", "weather": "多云转晴", "wind": "微风", "week": "星期二", "date": "20151013" }, "day_20151014": { "temperature": "17℃~27℃", "weather": "晴", "wind": "北风微风", "week": "星期三", "date": "20151014" }, "day_20151015": { "temperature": "17℃~28℃", "weather": "晴", "wind": "北风微风", "week": "星期四", "date": "20151015" }, "day_20151016": { "temperature": "17℃~30℃", "weather": "晴", "wind": "北风微风", "week": "星期五", "date": "20151016" }, "day_20151017": { "temperature": "17℃~30℃", "weather": "晴", "wind": "北风微风", "week": "星期六", "date": "20151017" } } }, "error_code": 0 }
继续使用 Dictionary 定义类:
public class WeatherRootobject { public string resultcode { get; set; } public string reason { get; set; } public Result result { get; set; } public int error_code { get; set; } } public class Result { public Sk sk { get; set; } public Today today { get; set; } public Dictionary<string, Weather> future { get; set; } } public class Sk { public string temp { get; set; } public string wind_direction { get; set; } public string wind_strength { get; set; } public string humidity { get; set; } public string time { get; set; } } public class Today { public string temperature { get; set; } public string weather { get; set; } public string wind { get; set; } public string week { get; set; } public string city { get; set; } public string date_y { get; set; } public string dressing_index { get; set; } public string dressing_advice { get; set; } public string uv_index { get; set; } public string comfort_index { get; set; } public string wash_index { get; set; } public string travel_index { get; set; } public string exercise_index { get; set; } public string drying_index { get; set; } } public class Weather { public string temperature { get; set; } public string weather { get; set; } public string wind { get; set; } public string week { get; set; } public string date { get; set; } }
然后反序列化输出:
WeatherRootobject weathers = JsonConvert.DeserializeObject<WeatherRootobject>(json); foreach (var temp in weathers.result.future) { Console.WriteLine(String.Format("Day:{0},Week:{1},Temperature:{2}", temp.Key, temp.Value.week, temp.Value.temperature)); }
结果如下:
作者:sun8134
本文版权归作者和博客园共有,欢迎转载,但未经作者同意必须保留此段声明,且在文章页面明显位置给出原文连接,否则保留追究法律责任的权利。