lua 读写本地json文件。 ｜ string和table的转化

 

1.

 cjson.encode
 cjson.decode
和System.IO.File进行json文件的读写。

   m.JsonPath = 'Assets/debug_cfg.json'
   local text = File.ReadAllText(m.JsonPath)
   local jsonInfos = cjson.decode(text)
   m.templateKeyName = jsonInfos[m.prefKeyName] or "" 20   m.templateInfo = self:stringToTable(jsonInfos[m.templateKeyName] or "")

　　

  local text = File.ReadAllText(m.JsonPath)
  local jsonInfos = cjson.decode(text)
  jsonInfos[m.prefKeyName] = saveName
  jsonInfos[saveName] = saveStr
  local saveInfo = cjson.encode(jsonInfos)
  File.WriteAllText(m.addonDebugJsonPath, saveInfo)

　

2.
string 和 table的相互转化。 string存储在PlayerPrefs中

 1 function m:serialize(obj)
 2   local lua = ""
 3   local t = type(obj)
 4   if t == "number" then
 5     lua = lua .. obj
 6   elseif t == "boolean" then
 7     lua = lua .. tostring(obj)
 8   elseif t == "string" then
 9     lua = lua .. string.format("%q", obj)
10   elseif t == "table" then
11     lua = lua .. "{"
12     for k, v in pairs(obj) do
13       lua = lua .. "[" .. self:serialize(k) .. "]=" .. self:serialize(v) .. ","
14     end
15     local metatable = getmetatable(obj)
16     if metatable ~= nil and type(metatable.__index) == "table" then
17       for k, v in pairs(metatable.__index) do
18         lua = lua .. "[" .. self:serialize(k) .. "]=" .. self:serialize(v) .. ","
19       end
20     end
21     lua = lua .. "}"
22   elseif t == "nil" then
23     return nil
24   else
25     error("can not serialize a " .. t .. " type.")
26   end
27   return lua
28 end
29 
30 function m:table2string(tablevalue)
31   local stringtable = self:serialize(tablevalue)
32   return stringtable
33 end
34 
35 function m:stringToTable(str)
36   local _result = loadstring("return " .. str);
37   return _result();
38 end

 
posted @ 2022-06-10 18:41  sun_dust_shadow  阅读(866)  评论(0)  编辑  收藏  举报