摘要: var fs = require("fs"); var arguments = (process.argv.splice(2))[0]; console.log('所传递的参数是:', arguments); var json = require("./api.json"); let str = ' 阅读全文
posted @ 2020-05-08 16:26 rrranmo 阅读(348) 评论(0) 推荐(0) 编辑