[second]Edit Distance

 

    int minDistance(string word1, string word2) {
        // Note: The Solution object is instantiated only once and is reused by each test case.
        int m = word1.size();
        int n = word2.size();
        
        vector<vector<int>> dp(m+1,vector<int>(n+1,0));
        int i,j;
        for(j=0;j<=n;j++)
            dp[0][j] = j;
        for(i=1;i<=m;i++)
            dp[i][0] = i;
        for(i=1;i<=m;i++)
        {
            for(j=1;j<=n;j++)
            {
                if(word1[i-1]==word2[j-1])
                    dp[i][j] = dp[i-1][j-1];
                else
                    dp[i][j] = min(dp[i-1][j-1],min(dp[i-1][j],dp[i][j-1]))+1;
            }
        }
        
        return dp[m][n];
    }

  

posted @ 2013-10-05 14:11  summer_zhou  阅读(152)  评论(0编辑  收藏  举报