Decode Ways
Q:
A message containing letters from A-Z
is being encoded to numbers using the following mapping:
'A' -> 1 'B' -> 2 ... 'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.
For example,
Given encoded message "12"
, it could be decoded as "AB"
(1 2) or "L"
(12).
The number of ways decoding "12"
is 2.
A: 一维动态规划
int numDecodings(string s) { // Start typing your C/C++ solution below // DO NOT write int main() function if(s.empty()||s[0]=='0') return 0; vector<int> dp(s.size()+1); dp[0] = 1; dp[1] = 1; for(int i=2;i<=s.size();i++) { if(s[i-1]=='0') { if(s[i-2]<='2'&&s[i-2]>'0') dp[i] = dp[i-2]; else return 0; }else { if(s[i-2]=='0'||s[i-2]>'2'||(s[i-2]=='2'&&s[i-1]>'6')) dp[i] = dp[i-1]; else dp[i] = dp[i-1]+dp[i-2]; } } return dp[s.size()]; }
更简洁的作法:
int numDecodings(string s) { // Start typing your C/C++ solution below // DO NOT write int main() function if(s.empty()) return 0; int n = s.size(); vector<int> dp(n+1); dp[0] = 1; for(int i=1;i<=n;i++) { int c1=0,c2=0; //分别考虑dp[i-1]和dp[i-2] if(s[i-1]!='0') c1 = dp[i-1]; if(i>=2&&(s[i-2]=='1'||s[i-2]=='2'&&s[i-1]<='6')) c2 = dp[i-2]; dp[i] = c1+c2; } return dp[n]; }