django实现翻页
实现代码如下
from django.core.paginator import Paginator, PageNotAnInteger, EmptyPage from django.forms.models import model_to_dict def getProjectResultList(request): if request.method == 'POST': pageNo = int(request.POST['pageNo']) pageSize = int(request.POST['pageSize']) list = ProjectResult.objects.filter(prj_id=prj_id).order_by('-rst_id') paginator = Paginator(list, pageSize) totalCount = paginator.count try: list = paginator.page(pageNo) except PageNotAnInteger: list = paginator.page(1) except EmptyPage: list = paginator.page(1) data = [] for info in list: json_dict = model_to_dict(info) data.append(json_dict) data = {"code": 200, "msg": "success", "data": data, "totalCount": totalCount} data = json.dumps(data) return HttpResponse(data, content_type='application/json') except: pass
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 无需6万激活码!GitHub神秘组织3小时极速复刻Manus,手把手教你使用OpenManus搭建本
· C#/.NET/.NET Core优秀项目和框架2025年2月简报
· Manus爆火,是硬核还是营销?
· 一文读懂知识蒸馏
· 终于写完轮子一部分:tcp代理 了,记录一下