Learn Python the hard way, ex39 列表的操作
1 #!/usr/bin/python 2 #coding:utf-8 3 4 ten_things = "apples oranges crows telephone light sugar" 5 print "wait there's not 10 things in that list,let's fix that" 6 7 stuff = ten_things.split(' ') #10个东西，以' '间隔开 8 more_stuff = ["day","night","song","frisbee","corn","banana","girl","boy"] #更多的原料 9 10 while len(stuff) != 10: #取得List stuff的长度，当不等于10时循环 11 next_one = more_stuff.pop() #截取more_stuff的最后一个元素（默认值） 12 print "adding:",next_one #输出pop取得的值 13 stuff.append(next_one) #使用append将之前截取的值赋予list：stuff 14 print "there's %d items now" % len(stuff) 15 16 print "there we go : ",stuff 17 18 print "let's do some things with stuff" 19 20 print stuff[1] #第二个元素，list从0计数 21 print stuff[-1] #whoa!fancy 最后一个元素(-1) 22 print stuff.pop() 23 print ' '.join(stuff) #what?cool! 24 print '#'.join(stuff[3:5]) # super stellar
Output:
1 wait there's not 10 things in that list,let's fix that 2 adding: boy 3 there's 7 items now 4 adding: girl 5 there's 8 items now 6 adding: banana 7 there's 9 items now 8 adding: corn 9 there's 10 items now 10 there we go : ['apples', 'oranges', 'crows', 'telephone', 'light', 'sugar', 'boy', 'girl', 'banana', 'corn'] 11 let's do some things with stuff 12 oranges 13 corn 14 corn 15 apples oranges crows telephone light sugar boy girl banana 16 telephone#light
加分题的一些参考： Python 面向对象编程 函数式编程
