[Swift]LeetCode93. 复原IP地址 | Restore IP Addresses
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➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/)
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/9936814.html
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Given a string containing only digits, restore it by returning all possible valid IP address combinations.
Example:
Input: "25525511135"
Output: ["255.255.11.135", "255.255.111.35"]
给定一个只包含数字的字符串,复原它并返回所有可能的 IP 地址格式。
示例:
输入: "25525511135"
输出: ["255.255.11.135", "255.255.111.35"]
16ms
1 class Solution { 2 func restoreIpAddresses(_ s: String) -> [String] { 3 if s.characters.count < 4 || s.characters.count > 12 { 4 return [] 5 } 6 7 let characters = Array(s.characters) 8 var result = [String]() 9 var candidate = [String]() 10 11 backtracking(characters, 0, &candidate, &result) 12 13 return result 14 } 15 private func backtracking(_ characters: [Character], _ pos: Int, _ candidate: inout [String], _ result: inout [String]) { 16 if candidate.count == 4 { 17 result.append(candidate.joined(separator: ".")) 18 return 19 } 20 21 let charsLeft = characters.count - pos 22 let groupsLeft = 4 - candidate.count 23 let minLen = groupsLeft == 1 ? charsLeft - groupsLeft + 1 : 1 24 let maxLen = characters[pos] == "0" ? 1 : min(3, charsLeft - groupsLeft + 1) 25 26 if minLen > maxLen { 27 return 28 } 29 30 for len in minLen...maxLen { 31 let num = String(characters[pos..<(pos + len)]) 32 if Int(num)! > 255 { 33 continue 34 } 35 candidate.append(num) 36 backtracking(characters, pos + len, &candidate, &result) 37 candidate.removeLast() 38 } 39 } 40 }