[Swift]LeetCode933. 最近的请求次数 | Number of Recent Calls

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Write a class RecentCounter to count recent requests.

It has only one method: ping(int t), where t represents some time in milliseconds.

Return the number of pings that have been made from 3000 milliseconds ago until now.

Any ping with time in [t - 3000, t] will count, including the current ping.

It is guaranteed that every call to ping uses a strictly larger value of t than before.

Example 1:

Input: inputs = ["RecentCounter","ping","ping","ping","ping"], inputs = [[],[1],[100],[3001],[3002]]
Output: [null,1,2,3,3]

Note:

1. Each test case will have at most 10000 calls to ping.
2. Each test case will call ping with strictly increasing values of t.
3. Each call to ping will have 1 <= t <= 10^9.

---

写一个 RecentCounter 类来计算最近的请求。

它只有一个方法：ping(int t)，其中 t 代表以毫秒为单位的某个时间。

返回从 3000 毫秒前到现在的 ping 数。

任何处于 [t - 3000, t] 时间范围之内的 ping 都将会被计算在内，包括当前（指 t 时刻）的 ping。

保证每次对 ping 的调用都使用比之前更大的 t 值。

示例：

输入：inputs = ["RecentCounter","ping","ping","ping","ping"], inputs = [[],[1],[100],[3001],[3002]]
输出：[null,1,2,3,3]

提示：

1. 每个测试用例最多调用 10000 次 ping。
2. 每个测试用例会使用严格递增的 t 值来调用 ping。
3. 每次调用 ping 都有 1 <= t <= 10^9。

---

916ms

class RecentCounter {
  var pings: [Int]
  var currI: Int
  
  init() {
    pings = []
    currI = 0
  }
  
  func ping(_ t: Int) -> Int {
    pings.append(t)
    
    while t - pings[currI] > 3000 {
      currI += 1
    }
    
    return pings.count - currI
  }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * let obj = RecentCounter()
 * let ret_1: Int = obj.ping(t)
 */
 

---

920ms

class RecentCounter {

    private var callTime: [Int] = []
    private var lastFits: Int = 0
    private let timeLimite: Int = 3000
    
    init() {
        
    }

    func ping(_ t: Int) -> Int {
        callTime.append(t)
        while t - callTime[lastFits] > timeLimite {
            lastFits += 1
        }
        return callTime.count - lastFits
    }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * let obj = RecentCounter()
 * let ret_1: Int = obj.ping(t)
 */
 

---

944ms

class RecentCounter {

     var nums: [Int]!
    
    init() {
        nums = [Int]()
    }
    
    func ping(_ t: Int) -> Int {
        nums.append(t)
        while nums[0] < t - 3000 {
            nums.remove(at: 0)
        }
        return nums.count
    }
}

---

968ms

class Node {
    var val: Int
    var next: Node?
    init(_ val: Int) {
        self.val = val
    }
}

class RecentCounter {

    var root: Node? 
    var current: Node?
    var counter = 0
    
    init() {
        
    }

    func ping(_ t: Int) -> Int {
        var newNode = Node(t)
        if current == nil {
            counter += 1
            root = newNode
            current = root
        } else {
            counter += 1
            current?.next = newNode
            current = current?.next
        }
        
        while let val = root?.val, val < t - 3000 {
            let temp = root?.next 
            root = temp
            counter -= 1
        } 
        return counter
    }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * let obj = RecentCounter()
 * let ret_1: Int = obj.ping(t)
 */
 

---

1204ms

class RecentCounter {
    var pq:Queue<Int> = Queue<Int>()

    init() {
        
    }

    func ping(_ t: Int) -> Int {
        pq.enQueue(t)
        while(!pq.isEmpty() && pq.getFirst()! < t-3000)
        {
            pq.deQueue()
        }
        return pq.count
    }
}

public struct Queue<T> {
    
    // 泛型数组：用于存储数据元素
    fileprivate var queue: [T] 

    // 返回队列中元素的个数
    public var count: Int {
        return queue.count
    }
    
    // 构造函数：创建一个空的队列
    public init() {
        queue = [T]()
    }
    
    //通过既定数组构造队列
    init(_ arr:[T]){
        queue = arr
    }
    
    // 检查队列是否为空
    // - returns: 如果队列为空，则返回true，否则返回false
    public func isEmpty() -> Bool {
        return queue.isEmpty
    }

    // 入队列操作：将元素添加到队列的末尾
    public mutating func enQueue(_ element: T) {
        queue.append(element)
    }
    
    // 出队列操作：删除并返回队列中的第一个元素
    public mutating func deQueue() -> T? {
        return queue.removeFirst()
    }
 
    // 返回队列中的第一个元素(不删除)
    public func getFirst() -> T? {
        return queue.first!
    }
}