为有牺牲多壮志，敢教日月换新天。

[Swift]LeetCode33. 搜索旋转排序数组 | Search in Rotated Sorted Array

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号：山青咏芝（shanqingyongzhi）
➤博客园地址：山青咏芝（https://www.cnblogs.com/strengthen/）
➤GitHub地址：https://github.com/strengthen/LeetCode
➤原文地址：https://www.cnblogs.com/strengthen/p/9899997.html 
➤如果链接不是山青咏芝的博客园地址，则可能是爬取作者的文章。
➤原文已修改更新！强烈建议点击原文地址阅读！支持作者！支持原创！
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

热烈欢迎，请直接点击！！！

进入博主App Store主页，下载使用各个作品！！！

注：博主将坚持每月上线一个新app！！！

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

Your algorithm's runtime complexity must be in the order of O(log n).

Example 1:

Input: nums = [4,5,6,7,0,1,2], target = 0
Output: 4

Example 2:

Input: nums = [4,5,6,7,0,1,2], target = 3
Output: -1

假设按照升序排序的数组在预先未知的某个点上进行了旋转。

( 例如，数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。

搜索一个给定的目标值，如果数组中存在这个目标值，则返回它的索引，否则返回 -1 。

你可以假设数组中不存在重复的元素。

你的算法时间复杂度必须是 O(log n) 级别。

示例 1:

输入: nums = [4,5,6,7,0,1,2], target = 0
输出: 4

示例 2:

输入: nums = [4,5,6,7,0,1,2], target = 3
输出: -1
12ms
 1 class Solution {
 2     func search(_ nums: [Int], _ target: Int) -> Int {
 3         guard nums.count > 0 else { return -1 }
 4         return search(0, nums.count - 1, nums, target) ?? -1
 5     }
 6     
 7     func search(_ start: Int, _ end: Int, _ nums: [Int], _ target: Int) -> Int? {
 8         
 9         if (start == end) {
10             if nums[start] == target {
11                 return start
12             } else {
13                 return nil
14             }
15         }
16         
17         let mid = (start + end) / 2
18         
19         //if start to mid is sorted
20         if nums[start] <= nums[mid]  {
21             if target >= nums[start] && target <= nums[mid] {
22                 return search(start, mid, nums, target)
23             } else {
24                 return search(mid + 1, end, nums, target)
25             }
26             
27         } 
28             
29         //if mid to end is sorted
30             if target >= nums[mid + 1] && target <= nums[end] {
31                 return search(mid + 1, end, nums, target)
32             } else {
33                 return search(start, mid, nums, target)
34             }
35     }
36     
37 }

12ms

 1 class Solution {
 2     func search(_ nums: [Int], _ target: Int) -> Int {
 3         if nums.count <= 0 {
 4             return -1
 5         }
 6         
 7         if nums.first! == target {
 8             return 0
 9         }
10         
11         if nums.last! == target {
12             return nums.count - 1
13         }
14         
15         var low = 0
16         var high = nums.count - 1
17         var mid = (low + high) >> 1
18         while low <= high {
19             let vallow = nums[low]
20             let valhigh = nums[high]
21             let valmid = nums[mid]
22             
23             if vallow == target {
24                 return low
25             }
26             if valhigh == target {
27                 return high
28             }
29             if valmid == target {
30                 return mid;
31             }
32 
33             if target > valhigh {
34                 if target > vallow {
35                     if target > valmid {
36                         low += 1
37                         high -= 1
38                     } else {
39                         high = mid - 1
40                         low += 1
41                     }
42                 } 
43             } else {
44                 if target > vallow {
45                     if target > valmid {
46                         low = mid + 1;
47                     } else {
48                         high = mid - 1
49                     }
50                 } else {
51                     low += 1
52                     high -= 1
53                 }
54             }
55             mid = (low + high) >> 1
56             if target > valhigh && target < vallow {
57                 return -1
58             }
59         }
60         return -1
61     }
62 }

16ms

 1 class Solution {
 2     func search(_ nums: [Int], _ target: Int) -> Int {
 3         var left = 0
 4         var right = nums.count - 1
 5         var mid = 0
 6         
 7         while left <= right {
 8             mid = (right - left) / 2 + left
 9             
10             if nums[mid] == target {
11                 return mid
12             }
13             
14             if nums[mid] >= nums[left] {
15                 if nums[mid] > target && target >= nums[left] {
16                     right = mid - 1
17                 } else {
18                     left = mid + 1
19                 }
20             } else {
21                 if nums[mid] < target && target <= nums[right] {
22                     left = mid + 1
23                 } else {
24                     right = mid - 1
25                 }
26             }
27         }
28         return -1
29     }
30 }

16ms

 1 class Solution {
 2     func search(_ nums: [Int], _ target: Int) -> Int {
 3         if nums.count == 0 {
 4             return -1
 5         }
 6         
 7         var left = 0
 8         var right = nums.count - 1
 9         var middle = 0
10         
11         while left < right {
12             middle = (left + right) / 2
13             if nums[middle] == target {
14                 return middle
15             }
16             if nums[left] <= nums[middle] {
17                 if target >= nums[left] && target < nums[middle] {
18                     right = middle - 1
19                 } else {
20                     left = middle + 1
21                 }
22             } else {
23                 if target > nums[middle] && target <= nums[right] {
24                     left = middle + 1
25                 } else {
26                     right = middle - 1
27                 }
28             }
29         }
30         
31         return nums[left] == target ? left : -1
32     }
33 }

20ms

  1 class Solution {
  2     func search(_ nums: [Int], _ target: Int) -> Int {
  3        
  4         if nums.count == 0
  5         {
  6             return -1
  7         }
  8         var pivot = 0
  9         if nums.count < 3
 10         {
 11             for i in 0..<nums.count
 12             {
 13                 if nums[i] == target
 14                 {
 15                     return i
 16                 }
 17             }
 18             return -1
 19         }
 20         
 21         if nums.first == target
 22         {
 23             return 0
 24         }
 25         if nums.last == target
 26         {
 27             return nums.count-1
 28         }
 29         for i in 1..<nums.count-1
 30         {
 31             if nums[i-1] > nums[i] && nums[i] < nums[i+1]
 32             {
 33                 pivot = i
 34             }
 35         }
 36         
 37         var desSortedArr = Array(nums[0..<pivot])
 38         var acsSortedArr = Array(nums[pivot...nums.count-1])
 39         //print(desSortedArr)
 40         let indexA = acsBinarySearch(desSortedArr,0,desSortedArr.count-1,target)
 41         let indexB = acsBinarySearch(acsSortedArr,0,acsSortedArr.count-1,target)
 42         
 43         //print("pivot\(pivot)")
 44         //print("indexA\(indexA)")
 45         //print("indexB\(indexB)")
 46         if indexA >= 0
 47         {
 48             return indexA
 49         }else if indexB >= 0
 50         {
 51             return desSortedArr.count + indexB
 52         }
 53         return -1
 54     }
 55     
 56        func descBinarySearch(_ arr:[Int] , _ lo:Int,_ hi:Int, _ target:Int) -> Int
 57     {
 58         
 59         if lo <= hi
 60         {
 61             var mi = (lo+hi)/2
 62             
 63             if arr[mi] == target
 64             {
 65                 print("arr[mi]\(arr[mi])")
 66                 return mi
 67             }
 68             else if target > arr[mi]
 69             {
 70                 
 71                 if mi - 1 >= lo
 72                 {
 73                 return descBinarySearch(arr,lo,mi-1,target)
 74                 }
 75             }
 76             else if  target < arr[mi]
 77             {
 78                 if mi + 1 <= hi
 79                 {
 80                 return descBinarySearch(arr,mi+1,hi,target)
 81                 }
 82             }
 83         }
 84         return -1
 85     }
 86     
 87        func acsBinarySearch(_ arr:[Int] , _ lo:Int,_ hi:Int, _ target:Int) -> Int
 88     {
 89         
 90         if lo <= hi
 91         {
 92             var mi = (lo+hi)/2
 93             
 94             if arr[mi] == target
 95             {
 96                 return mi
 97             }
 98             else if target > arr[mi]
 99             {
100                  if mi + 1 <= hi
101                 {
102                 return acsBinarySearch(arr,mi+1,hi,target)
103                 }
104             }
105             else if  target < arr[mi]
106             {
107                
108                 if mi - 1 >= lo
109                 {
110                 return acsBinarySearch(arr,lo,mi-1,target)
111                 }
112                 
113             }
114         }
115         return -1
116     }
117 }

 32ms

 1 class Solution {
 2     func search(_ nums: [Int], _ target: Int) -> Int {
 3         var start = 0
 4         var end = nums.count-1
 5         
 6         while start <= end {
 7             let mid = start + (end - start)/2
 8             if nums[mid] == target {
 9                 return mid
10             }
11             
12             if nums[mid] >= nums[start] {   // 前半段排好序
13                 if nums[mid] > target && nums[start] <= target {
14                     end = mid-1
15                 }
16                 else {
17                     start = mid+1
18                 }
19             }
20             else {    // 后半段排好序
21                 if nums[mid] < target && nums[end] >= target {
22                     start = mid+1
23                 }
24                 else {
25                     end = mid-1
26                 }
27             }
28         }
29         
30         return -1
31     }
32 }






            

            
posted @ 
2018-11-03 10:53 
为敢技术 
阅读(558) 
评论(0) 
编辑 
收藏 
举报