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[SQL]LeetCode577.员工奖金 | Employee Bonus

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Select all employee's name and bonus whose bonus is < 1000.

Table:Employee

+-------+--------+-----------+--------+
| empId |  name  | supervisor| salary |
+-------+--------+-----------+--------+
|   1   | John   |  3        | 1000   |
|   2   | Dan    |  3        | 2000   |
|   3   | Brad   |  null     | 4000   |
|   4   | Thomas |  3        | 4000   |
+-------+--------+-----------+--------+
empId is the primary key column for this table.

Table: Bonus

+-------+-------+
| empId | bonus |
+-------+-------+
| 2     | 500   |
| 4     | 2000  |
+-------+-------+
empId is the primary key column for this table.

Example ouput:

+-------+-------+
| name  | bonus |
+-------+-------+
| John  | null  |
| Dan   | 500   |
| Brad  | null  |
+-------+-------+

选出所有奖金<1000元的雇员姓名及奖金数额

Table:Employee

+-------+--------+-----------+--------+
| empId |  name  | supervisor| salary |
+-------+--------+-----------+--------+
|   1   | John   |  3        | 1000   |
|   2   | Dan    |  3        | 2000   |
|   3   | Brad   |  null     | 4000   |
|   4   | Thomas |  3        | 4000   |
+-------+--------+-----------+--------+
 此表的主键列为empId。

Table: Bonus

+-------+-------+
| empId | bonus |
+-------+-------+
| 2     | 500   |
| 4     | 2000  |
+-------+-------+
 此表的主键列为empId。

Example ouput:

+-------+-------+
| name  | bonus |
+-------+-------+
| John  | null  |
| Dan   | 500   |
| Brad  | null  |
+-------+-------+

1 SELECT
2     Employee.name, Bonus.bonus
3 FROM
4     Employee
5         LEFT OUTER JOIN
6     Bonus ON Employee.empid = Bonus.empid
7 ;

 1 # Write your MySQL query statement below
 2 
 3 SELECT
 4     Employee.name, Bonus.bonus
 5 FROM
 6     Employee
 7         LEFT JOIN
 8     Bonus ON Employee.empid = Bonus.empid
 9 WHERE
10     bonus < 1000 OR bonus IS NULL
11 ;

 

posted @ 2018-10-25 19:50  为敢技术  阅读(407)  评论(0编辑  收藏  举报