[SQL]LeetCode183. 从不订购的客户 | Customers Who Never Order
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/)
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/9720985.html
➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
Suppose that a website contains two tables, the Customers
table and the Orders
table. Write a SQL query to find all customers who never order anything.
Table: Customers
.
+----+-------+ | Id | Name | +----+-------+ | 1 | Joe | | 2 | Henry | | 3 | Sam | | 4 | Max | +----+-------+
Table: Orders
.
+----+------------+ | Id | CustomerId | +----+------------+ | 1 | 3 | | 2 | 1 | +----+------------+
Using the above tables as example, return the following:
+-----------+ | Customers | +-----------+ | Henry | | Max | +-----------+
某网站包含两个表,Customers
表和 Orders
表。编写一个 SQL 查询,找出所有从不订购任何东西的客户。
Customers
表:
+----+-------+ | Id | Name | +----+-------+ | 1 | Joe | | 2 | Henry | | 3 | Sam | | 4 | Max | +----+-------+
Orders
表:
+----+------------+ | Id | CustomerId | +----+------------+ | 1 | 3 | | 2 | 1 | +----+------------+
例如给定上述表格,你的查询应返回:
+-----------+ | Customers | +-----------+ | Henry | | Max | +-----------+
方法:使用子查询和NOT IN
子句
算法:如果我们有一个订购过的客户列表,很容易知道谁从未订购过。
我们可以使用以下代码来获取此类列表。
select customerid from orders;
然后,我们可以NOT IN
用来查询不在此列表中的客户。
1 select customers.name as 'Customers' 2 from customers 3 where customers.id not in 4 ( 5 select customerid from orders 6 );
222ms
1 # Write your MySQL query statement below 2 SELECT Name as 'Customers' from Customers where Id not in (select CustomerId from Orders)