[Swift]LeetCode1153. 字符串转化 | String Transforms Into Another String
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➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(www.zengqiang.org))
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/11333863.html
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Given two strings str1
and str2
of the same length, determine whether you can transform str1
into str2
by doing zero or more conversions.
In one conversion you can convert all occurrences of one character in str1
to any other lowercase English character.
Return true
if and only if you can transform str1
into str2
.
Example 1:
Input: str1 = "aabcc", str2 = "ccdee"
Output: true
Explanation: Convert 'c' to 'e' then 'b' to 'd' then 'a' to 'c'. Note that the order of conversions matter.
Example 2:
Input: str1 = "leetcode", str2 = "codeleet"
Output: false
Explanation: There is no way to transform str1 to str2.
Note:
1 <= str1.length == str2.length <= 10^4
- Both
str1
andstr2
contain only lowercase English letters.
给出两个长度相同的字符串,分别是 str1
和 str2
。请你帮忙判断字符串 str1
能不能在 零次 或 多次 转化后变成字符串 str2
。
每一次转化时,将会一次性将 str1
中出现的 所有 相同字母变成其他 任何 小写英文字母(见示例)。
只有在字符串 str1
能够通过上述方式顺利转化为字符串 str2
时才能返回 True
,否则返回 False
。
示例 1:
输入:str1 = "aabcc", str2 = "ccdee" 输出:true 解释:将 'c' 变成 'e',然后把 'b' 变成 'd',接着再把 'a' 变成 'c'。注意,转化的顺序也很重要。
示例 2:
输入:str1 = "leetcode", str2 = "codeleet" 输出:false 解释:我们没有办法能够把 str1 转化为 str2。
提示:
1 <= str1.length == str2.length <= 10^4
str1
和str2
中都只会出现 小写英文字母
72ms
1 class Solution { 2 func canConvert(_ str1: String, _ str2: String) -> Bool { 3 if str1 == str2 {return true} 4 let n:Int = str1.count 5 var arr:[Int] = [Int](repeating:-1,count:26) 6 let arrS:[Int] = Array(str1).map{$0.ascii} 7 let arrT:[Int] = Array(str2).map{$0.ascii} 8 for i in 0..<n 9 { 10 var x:Int = arrS[i] - 97 11 var y:Int = arrT[i] - 97 12 if arr[x] == -1 13 { 14 arr[x] = y 15 } 16 else if arr[x] != y 17 { 18 return false 19 } 20 } 21 var has:Int = 0 22 for i in 0..<26 23 { 24 if arr[i] != -1 25 { 26 has += 1 27 } 28 } 29 var flag:Int = 0 30 for i in 0..<26 31 { 32 for j in (i + 1)..<26 33 { 34 if arr[i] != -1 && arr[j] != -1 && arr[i] == arr[j] 35 { 36 flag = 1 37 } 38 } 39 } 40 if has != 26 || flag != 0 {return true} 41 return false 42 } 43 } 44 45 //Character扩展 46 extension Character 47 { 48 //Character转ASCII整数值(定义小写为整数值) 49 var ascii: Int { 50 get { 51 return Int(self.unicodeScalars.first?.value ?? 0) 52 } 53 } 54 }