[Swift]LeetCode1033. 移动石子直到连续 | Moving Stones Until Consecutive

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号：山青咏芝（shanqingyongzhi）
➤博客园地址：山青咏芝（https://www.cnblogs.com/strengthen/）
➤GitHub地址：https://github.com/strengthen/LeetCode
➤原文地址：https://www.cnblogs.com/strengthen/p/10783233.html 
➤如果链接不是山青咏芝的博客园地址，则可能是爬取作者的文章。
➤原文已修改更新！强烈建议点击原文地址阅读！支持作者！支持原创！
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

热烈欢迎，请直接点击！！！

进入博主App Store主页，下载使用各个作品！！！

注：博主将坚持每月上线一个新app！！！

Three stones are on a number line at positions a, b, and c.

Each turn, let's say the stones are currently at positions x, y, z with x < y < z.  You pick up the stone at either position x or position z, and move that stone to an integer position k, with x < k < z and k != y.

The game ends when you cannot make any more moves, ie. the stones are in consecutive positions.

When the game ends, what is the minimum and maximum number of moves that you could have made?  Return the answer as an length 2 array: answer = [minimum_moves, maximum_moves]

Example 1:

Input: a = 1, b = 2, c = 5
Output: [1, 2]
Explanation: Move stone from 5 to 4 then to 3, or we can move it directly to 3.

Example 2:

Input: a = 4, b = 3, c = 2
Output: [0, 0]
Explanation: We cannot make any moves.

Note:

1. 1 <= a <= 100
2. 1 <= b <= 100
3. 1 <= c <= 100
4. a != b, b != c, c != a

---

三枚石子放置在数轴上，位置分别为 a，b，c。

每一回合，我们假设这三枚石子当前分别位于位置 x, y, z 且 x < y < z。从位置 x 或者是位置 z 拿起一枚石子，并将该石子移动到某一整数位置 k 处，其中 x < k < z 且 k != y。

当你无法进行任何移动时，即，这些石子的位置连续时，游戏结束。

要使游戏结束，你可以执行的最小和最大移动次数分别是多少？ 以长度为 2 的数组形式返回答案：answer = [minimum_moves, maximum_moves]

示例 1：

输入：a = 1, b = 2, c = 5
输出：[1, 2]
解释：将石子从 5 移动到 4 再移动到 3，或者我们可以直接将石子移动到 3。

示例 2：

输入：a = 4, b = 3, c = 2
输出：[0, 0]
解释：我们无法进行任何移动。

提示：

1. 1 <= a <= 100
2. 1 <= b <= 100
3. 1 <= c <= 100
4. a != b, b != c, c != a

---

Runtime: 8 ms

Memory Usage: 19.1 MB

class Solution {
    func numMovesStones(_ a: Int, _ b: Int, _ c: Int) -> [Int] {
        var arr:[Int] = [a,b,c].sorted(by:<)
        let a = arr[0]
        let b = arr[1]
        let c = arr[2]
        var minNum:Int = 0
        if b - a == 2 || c - b == 2
        {
            minNum +=  1
        }
        else
        {
            if b - a > 2
            {
                minNum +=  1
            }
            if  c - b > 2
            {
                minNum +=  1
            }
        }
        return [minNum, c - a - 2]
    }
}

---

8ms 

class Solution {
    func numMovesStones(_ a: Int, _ b: Int, _ c: Int) -> [Int] {
        let arr = [a, b, c].sorted()
        let a = arr[0]
        let b = arr[1]
        let c = arr[2]
        
        if b - a == 1 {
            if c - b == 1 {
                return [0, 0]
            }
            return [1, c - b - 1]
        } else if c - b == 1 {
            return [1, b - a - 1]
        } else {
            if b - a == 2 || c - b == 2 {
                return [1, c - a - 2]
            }
            return [2, c - a - 2]
        }
    }
}