[Swift]LeetCode1023. 驼峰式匹配 | Camelcase Matching

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A query word matches a given pattern if we can insert lowercase letters to the pattern word so that it equals the query. (We may insert each character at any position, and may insert 0 characters.)

Given a list of queries, and a pattern, return an answer list of booleans, where answer[i] is true if and only if queries[i] matches the pattern.

Example 1:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
Output: [true,false,true,true,false]
Explanation: 
"FooBar" can be generated like this "F" + "oo" + "B" + "ar".
"FootBall" can be generated like this "F" + "oot" + "B" + "all".
"FrameBuffer" can be generated like this "F" + "rame" + "B" + "uffer".

Example 2:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
Output: [true,false,true,false,false]
Explanation: 
"FooBar" can be generated like this "Fo" + "o" + "Ba" + "r".
"FootBall" can be generated like this "Fo" + "ot" + "Ba" + "ll".

Example 3:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
Output: [false,true,false,false,false]
Explanation: 
"FooBarTest" can be generated like this "Fo" + "o" + "Ba" + "r" + "T" + "est".

Note:

1. 1 <= queries.length <= 100
2. 1 <= queries[i].length <= 100
3. 1 <= pattern.length <= 100
4. All strings consists only of lower and upper case English letters.

---

如果我们可以将小写字母插入模式串 pattern 得到待查询项 query，那么待查询项与给定模式串匹配。（我们可以在任何位置插入每个字符，也可以插入 0 个字符。）

给定待查询列表 queries，和模式串 pattern，返回由布尔值组成的答案列表 answer。只有在待查项 queries[i] 与模式串 pattern匹配时， answer[i] 才为 true，否则为 false。

示例 1：

输入：queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
输出：[true,false,true,true,false]
示例：
"FooBar" 可以这样生成："F" + "oo" + "B" + "ar"。
"FootBall" 可以这样生成："F" + "oot" + "B" + "all".
"FrameBuffer" 可以这样生成："F" + "rame" + "B" + "uffer".

示例 2：

输入：queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
输出：[true,false,true,false,false]
解释：
"FooBar" 可以这样生成："Fo" + "o" + "Ba" + "r".
"FootBall" 可以这样生成："Fo" + "ot" + "Ba" + "ll".

示例 3：

输出：queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
输入：[false,true,false,false,false]
解释： 
"FooBarTest" 可以这样生成："Fo" + "o" + "Ba" + "r" + "T" + "est". 

提示：

1. 1 <= queries.length <= 100
2. 1 <= queries[i].length <= 100
3. 1 <= pattern.length <= 100
4. 所有字符串都仅由大写和小写英文字母组成。

---

Runtime: 8 ms

Memory Usage: 19.9 MB

class Solution {
    func camelMatch(_ queries: [String], _ pattern: String) -> [Bool] {
        var ans:[Bool] = [Bool]()
        for q in queries
        {
            ans.append(go(q,pattern))
        }
        return ans
    }
    
    func go(_ q:String,_ p:String) -> Bool
    {
        var pos:Int = 0
        var arrP:[Character] = Array(p)
        for c in q
        {
            if pos < p.count && c == arrP[pos]
            {
                pos += 1
            }
            else if c < "a" || c > "z"
            {
                return false
            }
        }
        return pos == p.count
    }
}

---

8ms

 

import Foundation

class Solution {  
    func camelMatch(_ queries: [String], _ pattern: String) -> [Bool] {
        var result = [Bool]()
        let pattern = Array(pattern)
        for q in queries {
            result.append(check(Array(q), pattern))
        }
        return result
    }
    
    func check(_ q: [Character], _ p: [Character]) -> Bool {
        if p.count > q.count { return false }
        var pIndex = 0   
        for i in 0..<q.count {
            if pIndex > p.count - 1 {
                if isUpperCase(q[i]) { return false }
            } else {
                if q[i] == p[pIndex] {
                    pIndex += 1
                } else {
                    if isUpperCase(q[i]) { return false }
                }
            }
        }
        return pIndex == p.count
    }
    
    func isUpperCase(_ c: Character) -> Bool {
        let tmd = String(c).unicodeScalars.first!
        return CharacterSet.uppercaseLetters.contains(tmd)
    }
}

---

12ms

class Solution {
    func camelMatch(_ queries: [String], _ pattern: String) -> [Bool] {
        var result = [Bool]()
        for query in queries {
            result.append(isSubsequnce(pattern, query))
        }
        return result
    }
    
    fileprivate func isSubsequnce(_ pattern: String, _ word: String) -> Bool {
        guard pattern.count <= word.count else {
            return false
        }
        var index1 = 0, index2 = 0
        let chars1 = Array(pattern)
        let chars2 = Array(word)
    
        let capitals1 = chars1.filter { String($0).uppercased() == String($0) }
        let capitals2 = chars2.filter { String($0).uppercased() == String($0) }
        guard capitals1 == capitals2 else {
            return false
        }
        
        while index1 < chars1.count && index2 < chars2.count {
            if chars1[index1] == chars2[index2] {
                index1 += 1
                index2 += 1
            } else {
                index2 += 1
            }
        }
        return (index1 == chars1.count && index2 == chars2.count) || index1 == chars1.count
    }
}