志,敢教日月换新天。为有牺牲多壮

[Swift]LeetCode881. 救生艇 | Boats to Save People

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址: https://www.cnblogs.com/strengthen/p/10602721.html 
➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

热烈欢迎,请直接点击!!!

进入博主App Store主页,下载使用各个作品!!!

注:博主将坚持每月上线一个新app!!!

The i-th person has weight people[i], and each boat can carry a maximum weight of limit.

Each boat carries at most 2 people at the same time, provided the sum of the weight of those people is at most limit.

Return the minimum number of boats to carry every given person.  (It is guaranteed each person can be carried by a boat.) 

Example 1:

Input: people = [1,2], limit = 3
Output: 1
Explanation: 1 boat (1, 2)

Example 2:

Input: people = [3,2,2,1], limit = 3
Output: 3
Explanation: 3 boats (1, 2), (2) and (3)

Example 3:

Input: people = [3,5,3,4], limit = 5
Output: 4
Explanation: 4 boats (3), (3), (4), (5)

Note:

  • 1 <= people.length <= 50000
  • 1 <= people[i] <= limit <= 30000

第 i 个人的体重为 people[i],每艘船可以承载的最大重量为 limit

每艘船最多可同时载两人,但条件是这些人的重量之和最多为 limit

返回载到每一个人所需的最小船数。(保证每个人都能被船载)。

 

示例 1:

输入:people = [1,2], limit = 3
输出:1
解释:1 艘船载 (1, 2)

示例 2:

输入:people = [3,2,2,1], limit = 3
输出:3
解释:3 艘船分别载 (1, 2), (2) 和 (3)

示例 3:

输入:people = [3,5,3,4], limit = 5
输出:4
解释:4 艘船分别载 (3), (3), (4), (5)

提示:

  • 1 <= people.length <= 50000
  • 1 <= people[i] <= limit <= 30000

664ms

 

复制代码
 1 class Solution {
 2     func numRescueBoats(_ people: [Int], _ limit: Int) -> Int {
 3         let people = people.sorted()
 4         var left = 0, right = people.count - 1
 5         var count = 0
 6         while left <= right {
 7             if people[left] + people[right] <= limit {
 8                 count += 1
 9                 left += 1
10                 right -= 1
11             } else {
12                 count += 1
13                 right -= 1
14             }
15         }
16         return count        
17     }
18 }
复制代码

Runtime: 708 ms
Memory Usage: 19.8 MB
复制代码
 1 class Solution {
 2     func numRescueBoats(_ people: [Int], _ limit: Int) -> Int {
 3         var people = people.sorted(by:<)
 4         var ans:Int = 0
 5         var hi:Int = people.count - 1
 6         var lo:Int = 0 
 7         while (hi >= lo)
 8         {
 9             if people[lo] + people[hi] <= limit
10             {
11                 lo += 1
12             }
13             hi -= 1
14             ans += 1
15         }
16         return ans
17     }
18 }
复制代码

764ms

复制代码
 1 class Solution {
 2     func numRescueBoats(_ people: [Int], _ limit: Int) -> Int {
 3         var people = people.sorted()
 4         var ans = 0, headIndex = 0, tailIndex = people.count - 1
 5         while headIndex <= tailIndex {
 6             ans += 1
 7             var lastTailIndex = tailIndex
 8             while tailIndex > headIndex {
 9                 if people[tailIndex]+people[headIndex] > limit {
10                     tailIndex -= 1
11                     if tailIndex == headIndex {
12                         ans += (lastTailIndex - headIndex)
13                         return ans
14                     }
15                 }else {
16                     ans += (lastTailIndex - tailIndex)
17                     tailIndex -= 1
18                     break
19                 }
20             }
21             headIndex += 1
22         }
23         return ans
24     }
25 }
复制代码

 

posted @   为敢技术  阅读(201)  评论(0编辑  收藏  举报
编辑推荐:
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
· 没有源码,如何修改代码逻辑?
阅读排行:
· 全程不用写代码,我用AI程序员写了一个飞机大战
· MongoDB 8.0这个新功能碉堡了,比商业数据库还牛
· DeepSeek 开源周回顾「GitHub 热点速览」
· 记一次.NET内存居高不下排查解决与启示
· 白话解读 Dapr 1.15:你的「微服务管家」又秀新绝活了
点击右上角即可分享
微信分享提示
哥伦布
09:09发布
哥伦布
09:09发布
3°
多云
东南风
3级
空气质量
相对湿度
47%
今天
中雨
3°/15°
周三
中雨
3°/13°
周四
小雪
-1°/6°