[Swift]LeetCode620. 有趣的电影 | Not Boring Movies
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1 Create table If Not Exists cinema (id int, movie varchar(255), description varchar(255), rating float(2, 1)) 2 Truncate table cinema 3 insert into cinema (id, movie, description, rating) values ('1', 'War', 'great 3D', '8.9') 4 insert into cinema (id, movie, description, rating) values ('2', 'Science', 'fiction', '8.5') 5 insert into cinema (id, movie, description, rating) values ('3', 'irish', 'boring', '6.2') 6 insert into cinema (id, movie, description, rating) values ('4', 'Ice song', 'Fantacy', '8.6') 7 insert into cinema (id, movie, description, rating) values ('5', 'House card', 'Interesting', '9.1')
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions.
Please write a SQL query to output movies with an odd numbered ID and a description that is not 'boring'. Order the result by rating.
For example, table cinema:
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 1 | War | great 3D | 8.9 | | 2 | Science | fiction | 8.5 | | 3 | irish | boring | 6.2 | | 4 | Ice song | Fantacy | 8.6 | | 5 | House card| Interesting| 9.1 | +---------+-----------+--------------+-----------+
For the example above, the output should be:
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 5 | House card| Interesting| 9.1 | | 1 | War | great 3D | 8.9 | +---------+-----------+--------------+-----------+
某城市开了一家新的电影院，吸引了很多人过来看电影。该电影院特别注意用户体验，专门有个 LED显示板做电影推荐，上面公布着影评和相关电影描述。
作为该电影院的信息部主管，您需要编写一个 SQL查询，找出所有影片描述为非 boring (不无聊) 的并且 id 为奇数 的影片，结果请按等级 rating 排列。
例如，下表 cinema:
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 1 | War | great 3D | 8.9 | | 2 | Science | fiction | 8.5 | | 3 | irish | boring | 6.2 | | 4 | Ice song | Fantacy | 8.6 | | 5 | House card| Interesting| 9.1 | +---------+-----------+--------------+-----------+
对于上面的例子，则正确的输出是为：
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 5 | House card| Interesting| 9.1 | | 1 | War | great 3D | 8.9 | +---------+-----------+--------------+-----------+
108ms
1 # Write your MySQL query statement below 2 select id, movie, description, rating 3 from cinema 4 where mod(id,2) = 1 AND description <> "boring" 5 order by rating desc
109ms
1 # Write your MySQL query statement below 2 select * from cinema where description != 'boring' and id % 2 = 1 order by rating desc
110ms
1 # Write your MySQL query statement below 2 select a.* from cinema as a where mod(a.id,2)=1 and a.description != 'boring' order by rating desc;
111ms
1 # Write your MySQL query statement below 2 select * 3 from cinema 4 where not description = "boring" and mod(id, 2) = 1 5 order by rating desc
115ms
1 # Write your MySQL query statement below 2 select * from cinema 3 where id%2 <> 0 4 and description not like "%boring%" 5 order by rating desc
