[Swift]LeetCode503. 下一个更大元素 II | Next Greater Element II

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Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn't exist, output -1 for this number.

Example 1:

Input: [1,2,1]
Output: [2,-1,2]
Explanation: The first 1's next greater number is 2; 
The number 2 can't find next greater number; 
The second 1's next greater number needs to search circularly, which is also 2.

Note: The length of given array won't exceed 10000.

给定一个循环数组（最后一个元素的下一个元素是数组的第一个元素），输出每个元素的下一个更大元素。数字 x 的下一个更大的元素是按数组遍历顺序，这个数字之后的第一个比它更大的数，这意味着你应该循环地搜索它的下一个更大的数。如果不存在，则输出 -1。

示例 1:

输入: [1,2,1]
输出: [2,-1,2]
解释: 第一个 1 的下一个更大的数是 2；
数字 2 找不到下一个更大的数； 
第二个 1 的下一个最大的数需要循环搜索，结果也是 2。

注意: 输入数组的长度不会超过 10000。

300ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3         if nums.isEmpty { return [] }
 4         let n = nums.count
 5         var result = [Int](repeating: -1, count: n)
 6         var stack = [Int]()
 7         
 8         for i in 0..<2 * n {
 9             while !stack.isEmpty && nums[stack.last!] < nums[i % n] {
10                 let top = stack.removeLast()
11                 result[top] = nums[i % n]
12             }
13             if i < n {
14                 stack.append(i)
15             }
16         }
17         
18         return result
19     }
20 }

316ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3         var res = [Int](repeating: -1, count: nums.count)
 4         var s = [Int]()
 5         //5 3 2 1 4
 6         //
 7         for i in 0..<nums.count*2 {
 8             if s.isEmpty || nums[s[s.count-1]] > nums[i%nums.count] {
 9                 s.append(i%nums.count)
10             } else {
11                 while !s.isEmpty && nums[s[s.count-1]] < nums[i%nums.count] {
12                     res[s[s.count-1]] = nums[i%nums.count]
13                     s.removeLast()
14                 }
15                 s.append(i%nums.count)
16             }
17         }
18         return res
19     }
20 }

320ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3     
 4     var stack : [(val : Int, index : Int)] = []
 5     var result : [Int] = [Int](repeating: -1, count: nums.count)
 6     
 7     for (index, val) in nums.enumerated(){
 8         while !stack.isEmpty && stack.last!.val < val{
 9             let removed = stack.removeLast()
10             result[removed.index] = val
11         }
12         stack.append((val: val, index: index))
13     }
14     
15     for val in nums{
16         while !stack.isEmpty && stack.last!.val < val{
17             let removed = stack.removeLast()
18             result[removed.index] = val
19         }
20     }
21     return result
22    }
23 }

328ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3         var stack = [(Int, Int)]()
 4         var result = Array(repeating: -1, count: nums.count)
 5         
 6         for i in 0..<nums.count * 2 {
 7             let index = i % nums.count
 8             let this = nums[index]
 9             
10             while !stack.isEmpty && this > stack.last!.1 {
11                 let v = stack.removeLast()
12                 result[v.0] = this
13             }
14             stack.append((index, this))
15         }
16         
17         return result
18     }
19 }

380ms

 1 class Solution {
 2 
 3     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 4         if nums.count == 0 {
 5             return []
 6         }
 7         var result = Array(repeating: -1, count: nums.count)
 8         var stack = [Int]()
 9         let length = nums.count
10         for i in 0..<(2 * length)
11         {
12             let index = i % length
13             let current = nums[index]
14 
15             while !stack.isEmpty && current > nums[stack.last!] {
16                 result[stack.popLast()!] = nums[index]
17             }
18 
19             // 第二次循环时，不重复处理
20             if i < length {
21                 stack.append(index)
22             }
23         }
24         return result
25     }
26 }

432ms

 1 class Solution {
 2 
 3     struct IntegerStack {
 4         typealias Element = Int
 5 
 6         var isEmpty: Bool { return stack.isEmpty }
 7         var size: Int { return stack.count }
 8         var peek: Element? { return stack.last }
 9 
10         private var stack = [Element]()
11 
12         mutating func push(_ newElement: Element) {
13             stack.append(newElement)
14         }
15 
16         mutating func pop() -> Element? {
17             return stack.popLast()
18         }
19     }
20 
21     func nextGreaterElements(_ nums: [Int]) -> [Int] {
22         if nums.count == 0 {
23             return []
24         }
25         var result = Array(repeating: -1, count: nums.count)
26         var stack = IntegerStack()
27         stack.push(0)
28         var i = 1
29         let length = nums.count
30         while i < 2 * length - 1 && !stack.isEmpty {
31             let index = i % length
32             let current = nums[index]
33             if current > nums[stack.peek!] {
34                 result[stack.pop()!] = current
35                 if stack.isEmpty {
36                     stack.push(index)
37                     i += 1
38                 }
39             } else {
40                 stack.push(index)
41                 i += 1
42             }
43         }
44 
45         return result
46     }
47 }

536ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3     var result=[Int]()
 4          for (index,value) in nums.enumerated(){
 5             var i=index+1
 6           while i<nums.count{
 7               if value<nums[i]{
 8                   result.append(nums[i])
 9                   break
10               }
11               i+=1
12           }
13               var j=0
14              while result.count<index+1 {
15                 if value<nums[j]{
16                   result.append(nums[j])
17                   break
18               }
19             else if j==index{
20                 result.append(-1)
21                   break
22               }
23              j+=1                   
24             }
25          }
26        return result
27       }
28 }

600ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3     var result=[Int]()
 4         
 5          for (index,value) in nums.enumerated(){
 6              var  i=(index+1)==nums.count ? 0 : index+1
 7               result.append(-1)
 8              while i != index {
 9                 if value<nums[i]{
10                 result[index]=nums[i]
11                   break
12                 }
13              else{
14                  i+=1
15             if i==nums.count{
16                  i=0
17                  } 
18                }  
19             }
20          }
21         return result
22     }
23 }

624ms

 1 class Solution {
 2     func nextGreaterElements(_ nums: [Int]) -> [Int] {
 3         let t = nums + nums
 4         let r = helper(t, t)
 5         var results = [Int]()
 6         
 7         for i in 0..<nums.count {
 8             let this = r[i]
 9             if this == -1 {
10                 results.append(r[nums.count + i])
11             } else {
12                 results.append(this)
13             }
14         }
15         
16         return results
17     }
18     
19     func helper(_ findNums: [Int], _ nums: [Int]) -> [Int] {
20         var result = Array(repeating: -1, count: findNums.count)
21         var dict = [Int: [Int]]()
22         
23         for (i, num) in findNums.enumerated() {
24             if dict[num] == nil {
25                 dict[num] = [i]
26             } else {
27                 dict[num]?.append(i)
28             }
29         }
30         
31         for key in dict.keys {
32             dict[key]?.reverse()
33         }
34         
35         var stack = [Int]()
36         for num in nums {
37             while !stack.isEmpty && stack.last! < num {
38                 let c = stack.removeLast()
39                 
40                 if let i = dict[c]?.removeLast() {
41                     result[i] = num
42                 }
43             }
44             stack.append(num)
45         }
46         
47         return result
48     }
49 }

posted @ 2019-02-17 19:30 为敢技术阅读(241) 评论(0) 编辑收藏举报

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[Swift]LeetCode503. 下一个更大元素 II | Next Greater Element II

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