[Swift]LeetCode377. 组合总和 Ⅳ | Combination Sum IV
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➤微信公众号:山青咏芝(shanqingyongzhi)
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➤原文地址:https://www.cnblogs.com/strengthen/p/10278399.html
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Given an integer array with all positive numbers and no duplicates, find the number of possible combinations that add up to a positive integer target.
Example:
nums = [1, 2, 3] target = 4 The possible combination ways are: (1, 1, 1, 1) (1, 1, 2) (1, 2, 1) (1, 3) (2, 1, 1) (2, 2) (3, 1) Note that different sequences are counted as different combinations. Therefore the output is 7.
Follow up:
What if negative numbers are allowed in the given array?
How does it change the problem?
What limitation we need to add to the question to allow negative numbers?
给定一个由正整数组成且不存在重复数字的数组,找出和为给定目标正整数的组合的个数。
示例:
nums = [1, 2, 3] target = 4 所有可能的组合为: (1, 1, 1, 1) (1, 1, 2) (1, 2, 1) (1, 3) (2, 1, 1) (2, 2) (3, 1) 请注意,顺序不同的序列被视作不同的组合。 因此输出为 7。
进阶:
如果给定的数组中含有负数会怎么样?
问题会产生什么变化?
我们需要在题目中添加什么限制来允许负数的出现?
8ms
1 class Solution { 2 func combinationSum4(_ nums: [Int], _ target: Int) -> Int { 3 var memo = [Int](repeating: 0, count: target+1) 4 memo[0] = 1 5 for num in 1...target { 6 for i in 0..<nums.count { 7 if num >= nums[i] { 8 if memo[num] == Int.max - memo[num-nums[i]] { 9 return 1 10 }else if memo[num] > Int.max - memo[num-nums[i]]{ 11 return 0 12 } 13 memo[num] += memo[num-nums[i]] 14 } 15 } 16 } 17 return memo[target] 18 } 19 }
12ms
1 class Solution { 2 func combinationSum4(_ nums: [Int], _ target: Int) -> Int { 3 var dp = [Int](repeating: -1, count: target + 1) 4 dp[0] = 1 5 return _helper(nums, target, &dp) 6 } 7 8 fileprivate func _helper(_ nums: [Int], _ target: Int, _ dp: inout [Int]) -> Int { 9 if dp[target] != -1 { 10 return dp[target] 11 } 12 13 var res = 0 14 for num in nums { 15 if target >= num { 16 res += _helper(nums, target - num, &dp) 17 } 18 } 19 20 dp[target] = res 21 22 return res 23 } 24 }
12ms
1 class Solution { 2 func combinationSum4(_ nums: [Int], _ target: Int) -> Int { 3 if nums.isEmpty 4 { 5 return 0 6 } 7 var map:[Int:Int] = [Int:Int]() 8 return countCombination(nums, target, &map) 9 } 10 11 func countCombination(_ nums: [Int], _ target: Int,_ map:inout[Int:Int]) -> Int 12 { 13 if map[target] != nil 14 { 15 return map[target]! 16 } 17 var result:Int = 0 18 for i in 0..<nums.count 19 { 20 if nums[i] < target 21 { 22 result += countCombination(nums, target - nums[i], &map) 23 } 24 else if nums[i] == target 25 { 26 result += 1 27 } 28 } 29 map[target] = result 30 return result 31 } 32 }
20ms
1 class Solution { 2 3 var cache:[Int:Int] = [:] 4 var nums:[Int] = [] 5 6 func combinationSum4(_ nums: [Int], _ target: Int) -> Int { 7 return combinationSum(nums, target) 8 // return combs.count 9 } 10 11 func combinationSum(_ nums:[Int], _ target: Int) -> Int { 12 13 if self.cache[target] == nil { 14 var combs:Int = 0 15 16 for num in nums { 17 if num == target { 18 combs += 1 19 } 20 21 if num < target { 22 combs += combinationSum(nums, target-num) 23 } 24 } 25 26 self.cache[target] = combs 27 } 28 29 return self.cache[target]! 30 } 31 }
24ms
1 class Solution { 2 var cache = [Int: Int]() 3 func combinationSum4(_ nums: [Int], _ target: Int) -> Int { 4 cache = [:] 5 return helper(nums, target) 6 } 7 8 private func helper(_ nums: [Int], _ target: Int) -> Int { 9 guard target >= 0 else { return 0 } 10 guard target > 0 else { return 1 } 11 guard cache[target] == nil else { return cache[target]! } 12 13 let result = nums.map { helper(nums, target - $0) }.reduce(0) { $0 + $1 } 14 cache[target] = result 15 16 return result 17 } 18 }
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