[Swift]LeetCode316. 去除重复字母 | Remove Duplicate Letters
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/)
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/10260578.html
➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results.
Example 1:
"bcabc"
"abc"
Example 2:
"cbacdcbc"
"acdb"
给定一个仅包含小写字母的字符串,去除字符串中重复的字母,使得每个字母只出现一次。需保证返回结果的字典序最小(要求不能打乱其他字符的相对位置)。
示例 1:
"bcabc"
"abc"
示例 2:
"cbacdcbc"
"acdb"
32ms
1 class Solution { 2 func removeDuplicateLetters(_ s: String) -> String { 3 4 var counts = [Character: Int]() 5 var used = [Character:Bool]() 6 7 s.forEach { 8 counts[$0, default: 0] += 1 9 } 10 11 var ans = [Character]() 12 13 for ch in s { 14 counts[ch, default:0] -= 1 15 if used[ch, default: false] == true { 16 continue 17 } 18 19 while let last = ans.last, ch < last, counts[last]! > 0 { 20 used[last] = false 21 ans.removeLast() 22 } 23 ans.append(ch) 24 used[ch] = true 25 } 26 27 return String(ans) 28 } 29 }
36ms
1 extension Character { 2 var ascii: UInt32? { 3 guard let first = unicodeScalars.first else { 4 return nil 5 } 6 return first.isASCII == true ? first.value : nil 7 } 8 } 9 10 class Solution { 11 class IndexedTree { 12 var n: Int 13 var arr: [Int] 14 15 init(_ n: Int) { 16 self.n = n 17 arr = [Int](repeating: 0, count: n+1) 18 } 19 20 func insert(_ index: Int) -> Void { 21 var x = index 22 while x <= n { 23 arr[x] += 1 24 x = x + x&(-x) 25 } 26 } 27 28 func query(_ index: Int) -> Int { 29 var x = index 30 var sum = 0 31 while x > 0 { 32 sum += arr[x] 33 x = x&(x-1) 34 } 35 return sum 36 } 37 } 38 39 40 func transIndex(_ n: Int, _ index: Int) -> Int { 41 return n-index 42 } 43 44 func removeDuplicateLetters(_ s: String) -> String { 45 let charArr = Array(s) 46 var ans = "" 47 48 let n = charArr.count 49 if n == 0 { 50 return ans 51 } 52 53 var counts = [Int](repeating: 0, count: 26) 54 var indice = [Int?](repeating: nil, count: 26) 55 var used = [Bool](repeating: false, count: 26) 56 57 let indexedTree = IndexedTree(charArr.count) 58 let aAsc = "a".first!.ascii! 59 60 for (i, ch) in charArr.enumerated(){ 61 let ci = Int(ch.ascii!-aAsc) 62 counts[ci] += 1 63 } 64 65 var que = [Int]() 66 for (i, ch) in charArr.enumerated() { 67 let ci = Int(ch.ascii!-aAsc) 68 if counts[ci] == 0 { 69 continue 70 } 71 72 73 74 if indice[ci] == nil { 75 while let last = que.last { 76 if last > ci { 77 que.removeLast() 78 indice[last] = nil 79 } else { 80 break 81 } 82 } 83 84 indice[ci] = i 85 que.append(ci) 86 } 87 88 counts[ci] -= 1 89 if counts[ci] == 0 { 90 while let ii = que.first, ii <= ci { 91 let index = indice[ii]! 92 ans += String(charArr[index]) 93 indice[ii] = nil 94 counts[ii] = 0 95 que.removeFirst() 96 } 97 } 98 99 } 100 101 return ans 102 } 103 }
52ms
1 class Solution { 2 func removeDuplicateLetters(_ s: String) -> String { 3 let sArr = Array(s) 4 5 var counts = [Character : Int]() 6 7 for c in sArr { 8 if counts[c] == nil { 9 counts[c] = 1 10 }else { 11 counts[c]! += 1 12 } 13 } 14 15 var res = [Character]() 16 17 for c in sArr { 18 if !res.contains(c) { 19 while !res.isEmpty && counts[res.last!] != 0 && res.last! > c { 20 res.removeLast() 21 } 22 res.append(c) 23 24 } 25 counts[c]! -= 1 26 } 27 28 return String(res) 29 } 30 }
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
· 没有源码,如何修改代码逻辑?
· 全程不用写代码,我用AI程序员写了一个飞机大战
· MongoDB 8.0这个新功能碉堡了,比商业数据库还牛
· DeepSeek 开源周回顾「GitHub 热点速览」
· 记一次.NET内存居高不下排查解决与启示
· 白话解读 Dapr 1.15:你的「微服务管家」又秀新绝活了