腾讯// 反转字符串中的单词 III

给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。

示例 1:

输入: "Let's take LeetCode contest"
输出: "s'teL ekat edoCteeL tsetnoc" 

注意:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格。

先用split把各个单词分割开来,然后把各个单词翻转在连接成一个字符串,中间不要忘了加空格,最后一个不用加.

class Solution {
    public String reverseWords(String s) {
        String[] str = s.split(" ");
        String ns = "";
        for(int i = 0; i < str.length; i++){
            char[] c = new char[str[i].length()];
            for(int j = 0; j < str[i].length(); j++){
                c[j] = str[i].charAt(str[i].length()-j-1);
            }
            if(i!=str.length-1)
                ns+=String.valueOf(c)+" ";
            else
                ns+=String.valueOf(c);
        }
        return ns;
    }
}

 

posted @ 2018-10-22 20:40  strawqqhat  阅读(117)  评论(0编辑  收藏  举报
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