查找表类算法//字母异位词分组

给定一个字符串数组,将字母异位词组合在一起。字母异位词指字母相同,但排列不同的字符串。

示例:

输入: ["eat", "tea", "tan", "ate", "nat", "bat"],
输出:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

说明:

  • 所有输入均为小写字母。
  • 不考虑答案输出的顺序。

    给定一个字符串数组,将字母异位词组合在一起。字母异位词指字母相同,但排列不同的字符串。

    示例:

    输入: ["eat", "tea", "tan", "ate", "nat", "bat"],
    输出:
    [
      ["ate","eat","tea"],
      ["nat","tan"],
      ["bat"]
    ]

    说明:

  • 所有输入均为小写字母。
  • 不考虑答案输出的顺序。
class Solution {
    public List<List<String>> groupAnagrams(String[] strs) {
        if(strs == null || strs.length == 0) return new ArrayList<List<String>>();
        Map<String,List<String>> map = new HashMap<String,List<String>>();
        for(String s:strs){
            char[] ca = s.toCharArray();
            Arrays.sort(ca);
            String keyStr = String.valueOf(ca);
            if(!map.containsKey(keyStr)){
                map.put(keyStr,new ArrayList<String>());
            }
            map.get(keyStr).add(s);
        }
        return new ArrayList<List<String>>(map.values());
    }
}

 

class Solution {
public:
    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        vector<vector<string>> res;
        unordered_map<string,vector<string>> m;
        for(auto str:strs){
            string temp = str;
            sort(temp.begin(), temp.end());
            m[temp].push_back(str);
        }
        for(auto i:m){
            res.push_back(i.second);
        }
        return res;
    }
};

 

posted @ 2018-11-08 18:19  strawqqhat  阅读(96)  评论(0编辑  收藏  举报
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