哈希表//字符串中的第一个唯一字符

给定一个字符串,找到它的第一个不重复的字符,并返回它的索引。如果不存在,则返回 -1。

案例:

s = "leetcode"
返回 0.

s = "loveleetcode",
返回 2.

 

注意事项:您可以假定该字符串只包含小写字母。

class Solution {
    public int firstUniqChar(String s) {
        HashMap<Character,Integer> map = new HashMap<>();
        for(int i = 0; i < s.length(); i++){
            if(map.containsKey(s.charAt(i)))
                map.put(s.charAt(i),map.get(s.charAt(i))+1);
            else
                map.put(s.charAt(i),1);
        }
        for(int i = 0; i < s.length(); i++){
            if(map.get(s.charAt(i)) == 1){
                return i;
            }
        }
        return -1;
    }
}
class Solution {
public:
    int firstUniqChar(string s) {
        unordered_map<char,int> m;
        for(char c:s) m[c]++;
        for(int i = 0; i < s.size(); i++){
            if(m[s[i]] == 1) return i;
        }
        return -1;
    }
};

 

posted @ 2018-12-26 21:19  strawqqhat  阅读(108)  评论(0编辑  收藏  举报
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