poj 1008（注意计算一年的总日期，haab是365，tzo是260）

#include<iostream>
#include<cstring>
using namespace std;
int main(){
    char month[][10] = {"pop","no","zip","zotz","tzec",
                        "xul","yoxkin","mol","chen","yax",
                        "zac","ceh","mac","kankin","muan",
                        "pax","koyab","cumhu","uayet"};
    char period[][10] = {"imix","ik","akbal","kan","chicchan",
                         "cimi","manik","lamat","muluk","ok",
                         "chuen","eb","ben","ix","mem",
                         "cib","caban","eznab","canac","ahau"};
    int n;
    scanf("%d",&n);
    printf("%d\n",n);
    int day,year,haab_month_num;
    char haab_month[10];
    int count;
    int tzo_day,tzo_month,tzo_year;
    for(int i=0;i<n;i++){
        scanf("%d. %s %d",&day,haab_month,&year);
        count = 0;
        count += year*365 + day;
        for(int j=0;j<=18;j++){
            if(strcmp(haab_month,month[j])==0){
                //haab_month_num = j;
                count += j*20;
            }
        }
        tzo_year = count/260;
        tzo_month = count%260%20;
        tzo_day = count%260%13;
        printf("%d %s %d\n",tzo_day+1,period[tzo_month],tzo_year);
    }
    return 0;
}