随笔分类 - POJ
摘要：#include<iostream> #include<cstring> #include<cstdio> using namespace std; int row,col,n,k; int idx[26][26],ansx[900],ansy[900]; void print(){ printf(
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摘要：#include<iostream> #include<cstring> #include<cstdio> using namespace std; char c[10][20]; int data[10][20],idx[10][20],k,score; struct Node{ int x,y,
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摘要：#include<iostream> #include<algorithm> #include<cstring> #include<cstdio> using namespace std; const int maxn = 105; int a[maxn][maxn][2]; int n,data[
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摘要：#include<iostream> #include<algorithm> #include<cstdio> #include<cstring> using namespace std; int d[11],n,s,visit[50]; bool dfs(int num){ int i,j,wid
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摘要：#include<iostream> #include<cstring> #include<cstdio> using namespace std; const int maxn = 65; int d[10],p[10]; char a[maxn]; int t[maxn]; bool flag;
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int m,t,u,f,d,n,l[3],tmp,i,ans,sum; char a; scanf("%d%d%d%d%d",&m,&t,&u,&f,&d); l
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摘要：#include<iostream> #include<cstdio> #include<cmath> using namespace std; const double PI = 3.141592653589; int main(){ double w,h,v1,v2,v3,v4,x; while
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摘要：#include<iostream> #include<algorithm> #include<cstdio> using namespace std; const int maxn = 505; int n; int a[maxn][maxn],b[maxn][maxn],c[maxn][maxn
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摘要：#include<iostream> #include<cmath> #include<cstring> #include<cstdio> #include<algorithm> #include<ctime> #define ll long long using namespace std; co
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摘要：#include<iostream> #include<cstring> #include<cstdio> using namespace std; int main(){ int c,l,m,len[10005],p1,p2,s1,s2; char lr[10005][10]; scanf("%d
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int ans,sum,c,n,data[1005]; double avg,per; scanf("%d",&c); while(c--){ scanf("%d
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int n,p,q,data[25]; while(scanf("%d",&n)==1){ p = q = 0; for(int i=0;i<n;i++) sca
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int n,x,y; while(scanf("%d",&n)&&n){ int a = ~(unsigned)0>>1; while(n--){ scanf("
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摘要：#include<iostream> #include<cstdio> #include<cmath> #define PI 3.1415927 using namespace std; double a,b,c,tmp = acos(-1.0/2)*180/PI,x[4],y[4]; bool y
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摘要：#include<iostream> #include<cmath> #include<cstdio> using namespace std; int main(){ int n,a,b,c,d; char start[25][3],end[25][3]; scanf("%d",&n); for(
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摘要：#include<iostream> #include<cstring> #include<cstdio> using namespace std; int main(){ int i,j; bool flag = true; char data[1000]; int l = 0; while(ge
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int t,n,k,ans; scanf("%d",&t); while(t--){ scanf("%d",&n); if(n==1)printf("0\n");
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摘要：#include<iostream> #include<cstdio> #include<ctime> int main(){ int t,n,ans,base; scanf("%d",&t); while(t--){ scanf("%d",&n); base = 5; ans = 0; while
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摘要：#include<iostream> #include<cstdio> using namespace std; #define ll long long int main(){ ll N,M,ans,i,q; while(scanf("%lld%lld",&N,&M)==2&&N){ ans =
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摘要：#include<iostream> #include<cstdio> using namespace std; int main(){ int n,data[31]; while(scanf("%d",&n)==1&&n){ for(int i=1;i<=n;i++){ scanf("%d",&d
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