数学趣题——数字翻译器

问题：输入一个正整数N，输出英文表达。例如：1对应one

源码：

#include <stdio.h>

char data_1[19][11] = {"one", "two", "three", "four",
                       "five", "six", "seven", "eight",
                       "nine", "ten", "eleven", "twelve",
                       "thirteen", "forteen", "fifteen", "sixteen",
                       "seventeen", "eighteen", "ninteen"
                      };

char data_2[8][8] = {"twenty", "thirty", "forty", "fifty",
                     "sixty", "seventy", "eighty", "ninty"
                    };

void translation_A(long N);
void translation_B(long a);
void translation_C(long b);

void translation_A(long N)
{   /*翻译千位数*/
    long a;

    if(N == 0) {
        printf("Zero\n");
        return;
    }

    a = N / 1000;

    if(a != 0) {
        translation_B(a);
        printf("thousand ");
    }

    a = N % 1000;

    if(a != 0)
        translation_B(a);
}

void translation_B(long a)
{   /*翻译百位数*/
    long b;
    b = a / 100;

    if(b != 0) {
        translation_C(b);
        printf("hundred ");
    }

    b = a % 100;

    if(b != 0)
        translation_C(b);
}

void translation_C(long b)
{   /*翻译十位数和个位数*/
    long c;

    if(b <= 19)
        printf("%s ", data_1[b-1]);
    else
    {
        c = b / 10;
        printf("%s ", data_2[c-2]);
        c = b % 10;

        if(c != 0)
            printf("%s ", data_1[c-1]);
    }
}

int main()
{
    long N;
    printf("Please input a longeger from 0~999999\n");
    scanf("%ld", &N);
    translation_A(N);
    return 0;
}