摘要: SELECT message_id+1 from message_transmit_record a where not EXISTS ( select * from message_transmit_record b where b.message_id=a.message_id+1 ) AND 阅读全文
posted @ 2022-09-13 19:29 雾里看花的少年 阅读(45) 评论(0) 推荐(0) 编辑