摘要： 求平均数，巨水题#include <iostream>#include <iomanip>using namespace std;int main(void){ float a, sum = 0.0; for(int i = 0; i < 12; i++) { cin >> a; sum +=a; } cout << "$" << sum/12 << setprecision(2) << setiosflags(ios::fixed) << endl; return 0;} 阅读全文

摘要： POJ 1003 Hangover 水题//POJ 1003#include <iostream>using namespace std;float l[1001];int main(){ float f; l[0] = 0; for (int i = 1; i <= 1000; i++) l[i] = l[i-1]+1.0/(i+1); while (cin>>f, f!=0.00) { for (int i = 1; i <= 1000; i++) if (l[i] > f) { ... 阅读全文

摘要： //空间换时间 POJ 1002 487-3279#include <iostream>#include <cstring>#include <cstdlib>#include <stdio.h>using namespace std;int t[10000000];char change(char c){ if (c < 'Q') return (c-'A')/3+'2'; else return (c-'A'-1)/3+'2';}void add(char* 阅读全文