九度OJ 1439:Least Common Multiple
- 题目描述:
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The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
- 输入:
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Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
- 输出:
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For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
- 样例输入:
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2 3 5 7 15 6 4 10296 936 1287 792 1
- 样例输出:
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105 10296
#include <cstdio> //5 7 15 // 1 1 5 // 35 105 15 int gcd(int n,int m){ return m == 0 ? n: gcd(m,n%m); } int main(){ /* int n,m; while(scanf("%d%d",&n,&m) != EOF){ printf("%d\n",gcd(n,m)); }*/ int n,m; int b,temp; scanf("%d",&n); while(n--){ scanf("%d",&m); temp = 1; for(int i = 0;i < m;i++){ scanf("%d",&b); temp = b/gcd(temp,b)*temp; //a = temp; } printf("%d\n",temp); } }