最小费用最大流
用SPFA增广就可以了,(*^▽^*)
附上代码
#include<cstdio> #include<deque> #include<cstring> #define N 10000+10 #define M 50000+10 #define inf 1e9 #define ll long long using namespace std; int arnum=1,head[N]; struct arc{int next,to,cost,cap;}ar[M]; void add(int from,int to,int cap,int cost){ ar[++arnum].next=head[from]; ar[arnum].to=to; ar[arnum].cap=cap; ar[arnum].cost=cost; head[from]=arnum; } void insert(int from,int to,int cap,int cost){add(from,to,cap,cost);add(to,from,0,-cost);} int book[N],way[M],dis[N],pre[M]; deque<int>Q; ll Minflow,Mincost; bool SPFA(int n) { memset(book,0,sizeof(book)); memset(way,0,sizeof(way)); memset(pre,0,sizeof(pre)); for(int i=1;i<=n;i++)dis[i]=inf; Q.clear(); dis[1]=0,book[1]=1; Q.push_back(1); while(!Q.empty()) { int u=Q.front(); Q.pop_front(); book[u]=0; for(int i=head[u];i;i=ar[i].next) { int v=ar[i].to; int cap=ar[i].cap; if(cap>0&&dis[v]>dis[u]+ar[i].cost) { dis[v]=dis[u]+ar[i].cost; way[v]=u; pre[v]=i; if(!book[v]) { book[v]=1; if(Q.empty()||dis[v]>dis[Q.front()])Q.push_back(v); else Q.push_front(v); } } } } if(dis[n]==inf)return false; int minn=inf; for(int u=n;u!=1;u=way[u]) minn=min(minn,ar[pre[u]].cap); Minflow+=minn; Mincost+=minn*dis[n]; for(int u=n;u!=1;u=way[u]) { ar[pre[u]].cap-=minn; ar[pre[u]^1].cap+=minn; } return true; } int main() { int n,m;scanf("%d%d",&n,&m); for(int i=1;i<=m;i++){ int a,b,c,d; scanf("%d%d%d%d",&a,&b,&c,&d); insert(a,b,c,d); } while(SPFA(n)); printf("%lld %lld",Minflow,Mincost); return 0; }
夫君子之行,
静以修身,俭以养德;
非澹泊无以明志,
非宁静无以致远。
夫学须静也,才须学也;
非学无以广才,非志无以成学。
慆慢则不能励精,
险躁则不能冶性。
年与时驰,意与日去,
遂成枯落,多不接世。
悲守穷庐,将复何及!