摘要： #include<stdio.h>#include<string.h>void solve(){ int i, j, k, n, ans, cur; cur = 1, ans = 0; scanf("%d", &n); for(i = 0; i < n; i ++) { scanf("%d", &k); cur = (cur * (k % 9)) % 9; ans = (ans + cur) % 9; } printf("%d\n", ans == 0 ? 9 : ans);}int ma 阅读全文