python---django中权限框架设计

一:admin下的权限了解

推文:如何正确使用 Django的User Model

(一)默认权限表是在自带auth模块,中permission表中

可以使用has_perm方法获取用户是否有这个权限

(二)Django自定义权限

(1)添加表

from django.db import models
from django.contrib.auth.models import (
    BaseUserManager, AbstractBaseUser,PermissionsMixin
#BaseUserManager  用户管理基类,用于创建用户
#AbstractBaseUser 抽象类,声明一些必须字段,不会自己生产表,继承的子类才会,主要内容:class Meta abstract=True
#PermissionMixin 权限管理类,也是抽象类 )
class MyUserManager(BaseUserManager):   #用于创建用户,需要在settings文件中声明 def create_user(self, email, name, password=None): """ Creates and saves a User with the given email, date of birth and password. """ if not email: raise ValueError('Users must have an email address') user = self.model( email=self.normalize_email(email), name=name, ) user.set_password(password) user.save(using=self._db) return user def create_superuser(self, email, name, password): """ Creates and saves a superuser with the given email, date of birth and password. """ user = self.create_user( email, password=password, name=name, ) user.is_superuser = True user.save(using=self._db) return user class UserProfile(AbstractBaseUser,PermissionsMixin):   email = models.EmailField( verbose_name='email address', max_length=255, unique=True, ) name = models.CharField(max_length=128) is_active = models.BooleanField(default=True) is_staff = models.BooleanField(default=True) # is_admin = models.BooleanField(default=False)  #其中is_admin没有作用,is_superuser才是设置超级用户 role = models.ManyToManyField("Role",blank=True) #,null=Truenull has no effect on ManyToManyField.,null对于manytomanyfield无作用,会报警 objects = MyUserManager() #用户管理类和自定义用户表关联 USERNAME_FIELD = 'email' REQUIRED_FIELDS = ['name'] def __str__(self): return self.email def get_full_name(self): return self.email def get_short_name(self): return self.email

class Meta:
permissions = (  #用于管理权限条目
('自定义权限名','解释'),
)

 

(2)settings文件中设置

AUTH_USER_MODEL = 'repository.UserProfile' #上面的值表示Django应用的名称(必须位于INSTALLLED_APPS中)和你想使用的User模型的名称。

(3)在admin文件中设置展示内容

from django import forms
from django.contrib import admin
from django.contrib.auth.models import Group
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from django.contrib.auth.forms import ReadOnlyPasswordHashField

from repository.models import UserProfile


class UserCreationForm(forms.ModelForm):  #创建时显示的表单信息
    """A form for creating new users. Includes all the required
    fields, plus a repeated password."""
    password1 = forms.CharField(label='Password', widget=forms.PasswordInput)
    password2 = forms.CharField(label='Password confirmation', widget=forms.PasswordInput)

    class Meta:
        model = UserProfile
        fields = ('email', 'name')

    def clean_password2(self):  #对字段进行验证
        # Check that the two password entries match
        password1 = self.cleaned_data.get("password1")
        password2 = self.cleaned_data.get("password2")
        if password1 and password2 and password1 != password2:
            raise forms.ValidationError("Passwords don't match")
        return password2

    def save(self, commit=True):  
        # Save the provided password in hashed format
        user = super().save(commit=False)
        user.set_password(self.cleaned_data["password1"])
        if commit:
            user.save()
        return user


class UserChangeForm(forms.ModelForm):  #修改时显示的表单信息
    """A form for updating users. Includes all the fields on
    the user, but replaces the password field with admin's
    password hash display field.
    """
    password = ReadOnlyPasswordHashField()  #密码字段显示时是hash加密只读字段

    class Meta:
        model = UserProfile
        fields = ('email', 'password', 'name', 'is_active', 'is_superuser')

    def clean_password(self):
        # Regardless of what the user provides, return the initial value.
        # This is done here, rather than on the field, because the
        # field does not have access to the initial value
        return self.initial["password"]


class UserProfileAdmin(BaseUserAdmin):  #用于注册的表类
    # The forms to add and change user instances
    form = UserChangeForm
    add_form = UserCreationForm

    # The fields to be used in displaying the User model.
    # These override the definitions on the base UserAdmin
    # that reference specific fields on auth.User.
    list_display = ('email', 'name', 'is_superuser')
    list_filter = ('is_superuser',)
    fieldsets = (   #用于修改
        (None, {'fields': ('email', 'password')}),
        ('Personal info', {'fields': ('name',)}),
        ('Permissions', {'fields': ('is_active','is_staff','is_superuser','role','user_permissions','groups',)}),
    )
    # add_fieldsets is not a standard ModelAdmin attribute. UserAdmin
    # overrides get_fieldsets to use this attribute when creating a user.
    add_fieldsets = (   #用于添加
        (None, {
            'classes': ('wide',),
            'fields': ('email', 'name', 'password1', 'password2')}
        ),
    )
    search_fields = ('email',)
    ordering = ('email',)
    filter_horizontal = ('role','user_permissions',)

# Now register the new UserAdmin...
admin.site.register(UserProfile, UserProfileAdmin)
# ... and, since we're not using Django's built-in permissions,
# unregister the Group model from admin.
admin.site.unregister(Group)

 二:通用权限框架设计

(一)业务场景分析(如何去实现将不同权限分配给用户)

python---CRM用户关系管理

(二)权限管理分析

主要实现:将权限列表定义出来,与角色(用户组)相互关联就可以

权限列表实现:

 

 (三)实现方法

(1)定义权限列表文件,将权限列表定义。设置为装饰器,根据每个用户访问的url去反解,获取到对应的权限列表名,从而去数据库中获取,使用has_prem获取是否拥有权限。从而在用户访问url时进行判断

 permission_list.py(这部分最好是放入数据库中,可以改进

from kingadmin import permission_hook

perm_dict = {
    'repository_table_obj_list':['table_obj_list',"GET",[],{},permission_hook.view_my_own_customers],  
#第一个是url_name,第二个是访问方式,第三个是访问参数必须有的字段,第四个是字段中必须是指定的值,第五个是钩子函数,是对第三,第四参数的补充,实现动态验证
'repository_table_obj_change_view':['table_obj_change',"GET",[],{}], 'repository_table_obj_change': ['table_obj_change', "POST", [], {}], 'repository_table_obj_add_view': ['table_obj_add', "GET", [], {}], 'repository_table_obj_add': ['table_obj_add', "POST", [], {}], 'repository_table_obj_delete_view': ['table_obj_delete', "GET", [], {}], 'repository_table_obj_delete': ['table_obj_delete', "POST", [], {}], }
from django.conf.urls import url
from kingadmin import views

urlpatterns = [
    url(r"^login.html$",views.acc_login),
    url(r"^logout.html$", views.acc_logout,name="logout"),
    url(r"^$",views.app_index),
    url(r"^(\w+)/(\w+)/$",views.table_obj_list,name="table_obj_list"),
    url(r"^(\w+)/(\w+)/(\d+)/change/$", views.table_obj_change, name="table_obj_change"),
    url(r"^(\w+)/(\w+)/add/$", views.table_obj_add, name="table_obj_add"),
    url(r"^(\w+)/(\w+)/(\d+)/delete/$", views.table_obj_delete, name="table_obj_delete"),
]
urls文件,可以知道对应的url_name

resolve方法可以翻转获取url的数据

(2)permission文件,用于生成装饰器,验证权限列表

from .permission_list import perm_dict
from django.conf import settings
from django.core.urlresolvers import resolve
from django.shortcuts import render,redirect,HttpResponse

#对权限进行检测 def perm_check(
*args,**kwargs): request = args[0] resolve_url_obj = resolve(request.path)  #1,获取当前请求的url current_url_name = resolve_url_obj.url_name  #2,把url解析成url_name match_results = [None,] match_key = None if request.user.is_authenticated() is False:   #3,进行用户登录验证 return redirect(settings.LOGIN_URL) for permssion_key,permssion_val in perm_dict.items():
#从权限列表中获取url信息,以及钩子函数(重点) per_url_name
= permssion_val[0] per_method = permssion_val[1] per_args = permssion_val[2] per_kargs = permssion_val[3] per_hook_name = permssion_val[4] if len(permssion_val) > 4 else None if per_url_name == current_url_name: #4.匹配url_name if per_method == request.method: #5.匹配访问方法 args_matched = False #用于匹配参数args,一次参数失败,则失败 request_method_dict = getattr(request, per_method) for item in per_args:  #6.匹配参数 if request_method_dict.get(item,None): args_matched = True else: args_matched = False break #一次匹配不上,就跳出 else: #当不存在参数,列表为空时 args_matched = True kwargs_matched = False #用于匹配特定的参数 for k,v in per_kargs.items():  #7.匹配指定参数值 arg_val = request_method_dict.get(k,None) if arg_val == str(v): kwargs_matched = True else: kwargs_matched = False else: kwargs_matched = True hook_matched = False if per_hook_name:  #8.匹配钩子函数 hook_matched = per_hook_name(request) else: hook_matched = True match_results = [args_matched,kwargs_matched,hook_matched] if all(match_results): #9.都匹配了  全局验证,获取了权限名,用于下面数据库查询 match_key = permssion_key break if match_key: app_name,*per_name = match_key.split("_") perm_obj = "%s.%s"%(app_name,match_key) if request.user.has_perm(perm_obj):  #10.数据库查看用户是否被分配该权限 print("当前用户有权限") return True else: print("当前用户没有权限") return False else: print("未匹配到权限项,当前用户没有权限") return False
#装饰器函数 def check_permission(func): def inner(
*args,**kwargs): if not perm_check(*args,**kwargs): request = args[0] return render(request,"kingadmin/page_403.html") return func(*args,**kwargs) return inner

总结:

def perm_check(*args,**kwargs):
    1.获取当前请求的url,使用resolve解析获取url_name
    2.匹配用户是否登录,使用user.is_authenticated方法
    3.使用url_name去权限列表permission_list文件中的权限列表中去匹配权限项
    4.将权限项解析分为,per_url_name(权限url_name),per_method (url访问方法),per_args (获取的参数名),per_kargs (获取的参数值,字典),per_hook_name (获取的权限钩子函数)
    5.验证了上面的几部分,获取了权限名,然后去数据库中获取当前用户是否拥有该权限,使用user.has_perm(权限名<注意:权限名是由数据表应用加上权限名>)

(3)钩子函数案例(使当前用户只能访问自己的客户)

def view_my_own_customers(request):
    if str(request.user.id) == request.GET.get('consultant'):
        return True
    else:
        return False

 

posted @ 2018-06-04 20:51  山上有风景  阅读(3182)  评论(1编辑  收藏  举报