js获取url路径上的的参数 vue拿到url路径上的的参数

1. 由zz_text1页面跳转到zz_text2页面

2. zz_text1页面代码

<button style="width: 1rem;height: 0.6rem;line-height: 0.6rem;text-align: center;" @click="GoPage">跳转</button>
GoPage(){
       window.location.href="./zz_text2.html?id="+'1'+'&age='+'23'
}

3. zz_text2页面代码

var url = decodeURIComponent(location.search);
var theRequest = new Object();
if (url.indexOf("?") != -1) {
     var str = url.substr(1);
     var strs = str.split("&");
     for(var i = 0; i < strs.length; i ++) {
          theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
     }
}
console.log(url)
console.log(theRequest.id)
console.log(theRequest.age)

4. 效果图

 

posted @ 2021-08-30 10:41  srqsl  阅读(233)  评论(0编辑  收藏  举报