javascript实现跳转菜单

传统

这里要做的是，省略Go There按钮，选择菜单项后，直接跳转。

Html代码

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>转移菜单</title>
<script type="text/javascript" src="转移菜单.js"></script>
</head>
<body>
<form>
  <select id="newLocation">
  	<option selected="selected" value="">Select a topic</option>
    <option value="topic1.html">topic1</option>
    <option value="topic2.html">topic2</option>
    <option value="topic3.html">topic3</option>
    <option value="topic4.html">topic4</option>
    <option value="topic5.html">topic5</option>
  </select>
  
  <!--当浏览器不支持javascript或者禁用脚本运行时被调用-->
 <noscript>
 	<input type="submit" value="Go There!"/>
 </noscript>
 
</form>

</body>
</html>

Javascript脚本

window.onload=initForm;

//防止页面缓存，无法触发onload
window.onunload=function(){}
	
	function initForm(){
		document.getElementById("newLocation").selectIndex=0;
		document.getElementById("newLocation").onchange=jumpPage;
		
		}
		
		
	function jumpPage(){
		var newLoc=document.getElementById("newLocation");
		var newPage=newLoc.options[newLoc.selectedIndex].value;
	
		if (newPage!=""){
			window.location=newPage;
			}
		
		}

posted @ 2012-01-12 16:42 spring高手阅读(368) 评论(0) 编辑收藏举报

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javascript实现跳转菜单

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