使用js截取路径参数方法

1.根据传入的路径和参数名称截取

export function getUrlParams(href,name) {
  var reg = new RegExp("(^|\\?|&)"+ name +"=([^&]*)(\\s|&|$)", "i");
  if (reg.test(href)) {
    return unescape(RegExp.$2.replace(/\+/g, " "))
  };
  return "";
}

2.获取路径中的指定参数名称

export function getQueryString(name) {
  var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
  var r = window.location.search.substr(1).match(reg); 
  var context = "";
  if (r != null)
    context = r[2];
  reg = null;
  r = null;
  return context == null || context == "" || context == "undefined" ? "" : context;
}