JavaEE程序有一大路径陷阱,那就是ServletContext的getRealPath方法。我们常常使用getRealPath(“/”)来获得Web应用程序根目录的绝对路径。这是绝对要不得的!提供这个方法绝对是JavaEE API开发组的一大败笔。使用它,我们会万劫不复!

绝对不要使用ServletContext的getRealPath方法获取Web应用的路径!应该使用ServletContext的getResource()方法,直接使用相对于Web应用根目录的相对路径来获取资源。
ServletContext接口中定位资源的方法
getResource
java.net.URL getResource(java.lang.String path)
                         throws java.net.MalformedURLException
Returns a URL to the resource that is mapped to a specified path. The path must begin with a "/" and is interpreted as relative to the current context root.
This method allows the servlet container to make a resource available to servlets from any source. Resources can be located on a local or remote file system, in a database, or in a .war file.
The servlet container must implement the URL handlers and URLConnection objects that are necessary to access the resource.
This method returns null if no resource is mapped to the pathname.
Some containers may allow writing to the URL returned by this method using the methods of the URL class.
The resource content is returned directly, so be aware that requesting a .jsp page returns the JSP source code. Use a RequestDispatcher instead to include results of an execution.
This method has a different purpose than java.lang.Class.getResource, which looks up resources based on a class loader. This method does not use class loaders.
Parameters:
path - a String specifying the path to the resource
Returns:
the resource located at the named path, or null if there is no resource at that path
Throws:
java.net.MalformedURLException - if the pathname is not given in the correct form

getResourceAsStream
java.io.InputStream getResourceAsStream(java.lang.String path)
Returns the resource located at the named path as an InputStream object.
The data in the InputStream can be of any type or length. The path must be specified according to the rules given in getResource. This method returns null if no resource exists at the specified path.
Meta-information such as content length and content type that is available via getResource method is lost when using this method.
The servlet container must implement the URL handlers and URLConnection objects necessary to access the resource.
This method is different from java.lang.Class.getResourceAsStream, which uses a class loader. This method allows servlet containers to make a resource available to a servlet from any location, without using a class loader.
Parameters:
path - a String specifying the path to the resource
Returns:
the InputStream returned to the servlet, or null if no resource exists at the specified path
getRealPath
java.lang.String getRealPath(java.lang.String path)
Returns a String containing the real path for a given virtual path. For example, the path "/index.html" returns the absolute file path on the server's filesystem would be served by a request for "http://host/contextPath/index.html", where contextPath is the context path of this ServletContext..
The real path returned will be in a form appropriate to the computer and operating system on which the servlet container is running, including the proper path separators. This method returns null if the servlet container cannot translate the virtual path to a real path for any reason (such as when the content is being made available from a .war archive).
Parameters:
path - a String specifying a virtual path
Returns:
a String specifying the real path, or null if the translation cannot be performed
说明
可以看到,ServletContext接口中的getResource()等方法,可以找到任何从应用程序的根目录开始的资源。包括在.war包这样的压缩文件中。参数必须以/开头。
而我们常用的getRealPath(“/”)方法,在.war包发布时,就会失效。会返回null。
因此,我们应该避免使用getRealPath(“/”)这样的方法来获取应用程序的绝对路径。
如果你不想使用之前写过的助手类ClassLoaderUtil 的public static URL getExtendResource(String relativePath)方法,那么你应该使用ServletContext接口的
java.net.URL getResource(java.lang.String path)
                         throws java.net.MalformedURLException
方法,URL对象可以方便的转为URI,和String对象。
    尽管没有ServletContext的源码,但是我可以猜想到getResource等方法一定在底层使用了ClassLoader的getResource方法。
posted on 2012-03-12 09:29  七月逆流  阅读(381)  评论(0编辑  收藏  举报