SQL 优化之该走索引却不走索引的分析

 

分析案例:

1.走rule很快,但是收集了执行计划后却很慢

SQL> create table test(id int);

表已创建。

SQL> insert into test select 1 from dba_objects;

已创建49883行。

SQL> commit;

提交完成。

SQL> insert into test select 2 from user_objects where rownum<101;

已创建100行。

SQL> commit;

提交完成。

SQL> create index i_test_1 on test(id);

索引已创建。

SQL> analyze table test compute statistics;

表已分析。

SQL> set autot trace
SQL> set timing on
SQL> select * from test where id=2;

已选择100行。

已用时间:  00: 00: 00.01

执行计划
----------------------------------------------------------
Plan hash value: 1357081020

--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      | 24992 | 49984 |    20  (10)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| TEST | 24992 | 49984 |    20  (10)| 00:00:01 |
--------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("ID"=2)


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
         86  consistent gets
          0  physical reads
          0  redo size
       1690  bytes sent via SQL*Net to client
        451  bytes received via SQL*Net from client
          8  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
        100  rows processed

可以看出这里并没有走索引,可以对比rows和实际返回的行数100,得出这时候的统计信息并没有反应真实的情况

SQL> select /*+ rule */ * from test where id=2;

已选择100行。

已用时间:  00: 00: 00.00

执行计划
----------------------------------------------------------
Plan hash value: 3245211066

-------------------------------------
| Id  | Operation        | Name     |
-------------------------------------
|   0 | SELECT STATEMENT |          |
|*  1 |  INDEX RANGE SCAN| I_TEST_1 |
-------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - access("ID"=2)

Note
-----
   - rule based optimizer used (consider using cbo)


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
          9  consistent gets
          0  physical reads
          0  redo size
       1690  bytes sent via SQL*Net to client
        451  bytes received via SQL*Net from client
          8  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
        100  rows processed

已用时间:  00: 00: 00.01

从这里可以看出如果是走索引的话是很快的,大概已经明白了,这个字段是倾斜的,所以收集下直方图应该就能走正确的执行计划

SQL> analyze table test compute statistics for table for all indexes for all indexed columns;

表已分析。

已用时间:  00: 00: 00.37

SQL> select * from test where id=2;

已选择100行。

已用时间:  00: 00: 00.00

执行计划
----------------------------------------------------------
Plan hash value: 3245211066

-----------------------------------------------------------------------------
| Id  | Operation        | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
-----------------------------------------------------------------------------
|   0 | SELECT STATEMENT |          |   100 |   200 |     1   (0)| 00:00:01 |
|*  1 |  INDEX RANGE SCAN| I_TEST_1 |   100 |   200 |     1   (0)| 00:00:01 |
-----------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - access("ID"=2)


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
          9  consistent gets
          0  physical reads
          0  redo size
       1690  bytes sent via SQL*Net to client
        451  bytes received via SQL*Net from client
          8  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
        100  rows processed

//收集直方图后走了正确的执行计划


2.加hint也不走索引

a.隐式类型转换
 
  对于这个问题,10g可以根据执行计划下面的谓词部分来判断,而对于10g以前的版本可以根据强制加hint不走索引,
  对于index full scan和index fast full scan做为切入点


example:

执行计划
----------------------------------------------------------
Plan hash value: 4122059633

---------------------------------------------------------------------------
| Id  | Operation         | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |       |     1 |    29 |    58   (6)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| TEST1 |     1 |    29 |    58   (6)| 00:00:01 |
---------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter(TO_NUMBER("OBJECT_ID")=10000)  

从这里可以看出oracle隐式的把object_id变成了number类型,强制加hint看看

  1*  select /*+ index(test1) */ * from test1 where object_id=10000
SQL> /

未选定行


执行计划
----------------------------------------------------------
Plan hash value: 4122059633

---------------------------------------------------------------------------
| Id  | Operation         | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |       |     1 |    29 |    58   (6)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| TEST1 |     1 |    29 |    58   (6)| 00:00:01 |
---------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter(TO_NUMBER("OBJECT_ID")=10000)
 
确实加了hint也不走索引,既然已经知道了是因为隐式转换导致的不走索引,这时候可以有2个办法,避免隐式转换或者创建函数索引
 
  
b.索引失效


执行计划
----------------------------------------------------------
Plan hash value: 4122059633

---------------------------------------------------------------------------
| Id  | Operation         | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |       |     1 |    29 |    57   (4)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| TEST1 |     1 |    29 |    57   (4)| 00:00:01 |
---------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("OBJECT_ID"='10000')

 确认过这里的没有存在隐式类型转换,如果是10g的话,skip_unusable_indexes=true强制走索引会报错.
 检查索引的状态.

SQL> select status from user_indexes where table_name='TEST1';

STATUS
--------
UNUSABLE

索引失效了,只能rebuild,同时收集索引的统计信息,9i不要用alter index.. rebuild compute statistics;
因为这个会同时收集表的统计信息,10g以后没有问题,如果怕rebuild影响dml,那可以加上online选项

SQL> alter index i_test1_1 rebuild;

索引已更改。

SQL> analyze index i_test1_1 compute statistics;

索引已分析

SQL> set autot trace
SQL> select * from test1 where object_id='10000';

未选定行


执行计划
----------------------------------------------------------
Plan hash value: 3616871662

--------------------------------------------------------------------------------
---------

| Id  | Operation                   | Name      | Rows  | Bytes | Cost (%CPU)| T
ime     |

--------------------------------------------------------------------------------
---------

|   0 | SELECT STATEMENT            |           |     1 |    29 |     2   (0)| 0
0:00:01 |

|   1 |  TABLE ACCESS BY INDEX ROWID| TEST1     |     1 |    29 |     2   (0)| 0
0:00:01 |

|*  2 |   INDEX RANGE SCAN          | I_TEST1_1 |     1 |       |     1   (0)| 0
0:00:01 |

--------------------------------------------------------------------------------
---------


Predicate Information (identified by operation id):
---------------------------------------------------

   2 - access("OBJECT_ID"='10000')

这时候终于走索引


c.索引的访问路径oracle并没有考虑

主要讨论index fast full scan

index fast full scan类似全表扫描,只是把索引当作表来处理,支持并行和多块读
index fast full scan的前提是,索引必须满足这个查询,同时必须保证非空
(通过非空字段或者是在where条件中声明非空),最为典型的就是count(*)

SQL> create table test as select * from dba_objects;

表已创建。

SQL> create index i_test_1 on test(object_id);

索引已创建。

SQL> analyze table test compute statistics;

表已分析。

SQL> select count(*) from test;


执行计划
----------------------------------------------------------
Plan hash value: 1950795681

-------------------------------------------------------------------
| Id  | Operation          | Name | Rows  | Cost (%CPU)| Time     |
-------------------------------------------------------------------
|   0 | SELECT STATEMENT   |      |     1 |   154   (2)| 00:00:02 |
|   1 |  SORT AGGREGATE    |      |     1 |            |          |
|   2 |   TABLE ACCESS FULL| TEST | 49883 |   154   (2)| 00:00:02 |
-------------------------------------------------------------------


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
        690  consistent gets
          0  physical reads
          0  redo size
        410  bytes sent via SQL*Net to client
        385  bytes received via SQL*Net from client
          2  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
          1  rows processed

这里虽然有索引,但是oracle并不知道索引中是否有null值,所以无法走索引

SQL> select count(*) from test where object_id is not null;


执行计划
----------------------------------------------------------
Plan hash value: 1366347385

--------------------------------------------------------------------------------
--

| Id  | Operation             | Name     | Rows  | Bytes | Cost (%CPU)| Time
 |

--------------------------------------------------------------------------------
--

|   0 | SELECT STATEMENT      |          |     1 |     4 |    27   (4)| 00:00:01
 |

|   1 |  SORT AGGREGATE       |          |     1 |     4 |            |
 |

|*  2 |   INDEX FAST FULL SCAN| I_TEST_1 | 49882 |   194K|    27   (4)| 00:00:01
 |

--------------------------------------------------------------------------------
--


Predicate Information (identified by operation id):
---------------------------------------------------

   2 - filter("OBJECT_ID" IS NOT NULL)


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
        117  consistent gets
          0  physical reads
          0  redo size
        410  bytes sent via SQL*Net to client
        385  bytes received via SQL*Net from client
          2  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
          1  rows processed

select count(distinct object_id) from test;
select count(*) from (select object_id from test group by object_id);
这是itpub上的一个例子,严格来说这2个语句并不是等价的,第一个语句会忽略null,因此只要object_id上有索引
,同时索引比表小的情况就会用索引扫描代替全表扫描,而第二个语句则不会.
第一个语句和select count(*) from (select object_id from test where object_id is not null group by object_id);
是等价的.

3.统计信息不对

SQL> create table test as select * from dba_objects where 1=0;

表已创建。

SQL> analyze table test compute statistics;

表已分析。

SQL> insert into test select * from dba_objects;

已创建49920行。

SQL> commit;

提交完成。

SQL> create index i_test_1 on test(object_id);

索引已创建。

SQL> select * from test where object_id=10000;

未选定行


执行计划
----------------------------------------------------------
Plan hash value: 1357081020

--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |     1 |   177 |     2   (0)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| TEST |     1 |   177 |     2   (0)| 00:00:01 |
--------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("OBJECT_ID"=10000)


统计信息
----------------------------------------------------------
          1  recursive calls
          0  db block gets
        689  consistent gets
          0  physical reads
          0  redo size
        992  bytes sent via SQL*Net to client
        374  bytes received via SQL*Net from client
          1  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
          0  rows processed

从这里来判断统计信息错误,这个表大概60000多行,这里的cost=2,rows=1(实际上这里可能是0行),基本可以判断出表是没有统计信息的,
如果这个表的统计信息是正确的话,这个表肯定是小表,一般不可能导致比较大的逻辑读

posted @ 2010-11-08 10:46  无双的小宝  阅读(2921)  评论(0编辑  收藏  举报