java-Stream的总结

JAVA中的Stream

01.什么是Stream

Stream是JDK8中引入,Stream是一个来自数据源的元素序列并支持聚合操作。可以让你以一种声明的方式处理数据,Stream 使用一种类似用 SQL 语句从数据库查询数据的直观方式来提供一种对 Java 集合运算和表达的高阶抽象。Stream API可以极大提高Java程序员的生产力,让程序员写出高效率、干净、简洁的代码。

02.Stream特点

  • 元素:是特定类型的对象,形成一个序列。 Java中的Stream并不会存储元素,而是按需计算。
  • 数据源:流的来源可以是集合,数组,I/O channel等。
  • 过滤、聚合、排序等操作:类似SQL语句一样的操作, 比如filter, map, reduce, find, match, sorted等
  • Pipelining(流水线/管道): 中间操作都会返回流对象本身。 这样多个操作可以串联成一个管道, 如同流式风格(fluent style)。 这样做可以对操作进行优化, 比如延迟执行(laziness)和短路( short-circuiting)。
  • 内部迭代: 以前对集合遍历都是通过Iterator或者For-Each的方式, 显式的在集合外部进行迭代, 这叫做外部迭代。 Stream提供了内部迭代的方式。
  • 只能遍历一次:数据流的从一头获取数据源,在流水线上依次对元素进行操作,当元素通过流水线,便无法再对其进行操作

image-20220617093802599

一个stream是由三部分组成的。数据源,零个或一个或多个中间操作,一个或零个终止操作。
中间操作是对数据的加工,注意:中间操作是lazy操作,并不会立马启动,需要等待终止操作才会执行。
终止操作是stream的启动操作,只有加上终止操作,stream才会真正的开始执行。

03.Stream入门案例

//要求把list1中的空字符串过滤掉,并把结果保存在列表中
public class Test {
    public static void main(String[] args) {
        List<String> list1 = Arrays.asList("ab", "", "cd", "ef", "mm","", "hh");
        System.out.println(list1);//[ab, , cd, ef, mm, , hh]
        List<String> result = list1.stream().filter(s -> !s.isEmpty()).collect(Collectors.toList());
        System.out.println(result);//[ab, cd, ef, mm, hh]
    }
}

上面这个例子可以看出list1是一个字符串的列表,其中有两个空字符串,在stream的操作过程中,我们使用了stream()、filter()、collect()等方法,在filter()过程中,我们引入了Lambda表达式s->!s.isEmpty(),结果是把两个空字符串过滤掉后,形成了一个新的列表result。
上面这个需求如果我们使用传统的代码完成如下:

public class Test {
    public static void main(String[] args) {
        List<String> list1 = Arrays.asList("ab", "", "cd", "ef", "mm","", "hh");
        List<String> result = new ArrayList<>();
        for (String str : list1) {
            if(str.isEmpty()){
                continue;
            }
            result.add(str);
        }
        System.out.println(result);
    }
}

比较两段代码,我们可以发现在第二段代码中我们自己创建了一个字符串对象列表,开启一个for循环遍历字符串对象列表,在for循环中判断是否当前的字符串是空串,如果不是,加到结果列表中。而在第一段程序中,我们并不需要自己开启for循环遍历,stream会在内部做迭代,我们只需要传入我们的过滤条件就可以了,最后这个字符串列表也是代码自动创建出来的,并且把结果放入了列表中,可以看出,第一段代码简洁优雅。

04.Stream操作分类

image-20220617233709237

  • 无状态:指元素的处理不受之前元素的影响;
  • 有状态:指该操作只有拿到所有元素之后才能继续下去。
  • 非短路操作:指必须处理所有元素才能得到最终结果;
  • 短路操作:指遇到某些符合条件的元素就可以得到最终结果,如 A || B,只要A为true,则无需判断B的结果。

05.Stream使用案例

5.1.创建流

5.1.1.使用Collection下的 stream() 和 parallelStream() 方法

public class Test {
    public static void main(String[] args) {
        List<String> list = new ArrayList<>();
        Stream<String> stream = list.stream(); //获取一个串行流
        Stream<String> parallelStream = list.parallelStream(); //获取一个并行流
    }
}

5.1.2.使用Arrays 中的 stream() 方法,将数组转成流

public class Test {
    public static void main(String[] args) {
        Integer[] nums = new Integer[10];
        Stream<Integer> stream = Arrays.stream(nums);
    }
}

5.1.3.使用Stream中的静态方法:of()、iterate()、generate()

public class Test {
    public static void main(String[] args) {
        Stream<Integer> stream = Stream.of(1,2,3,4,5,6);
        stream.forEach(System.out::print);//1 2 3 4 5 6
        System.out.println("==========");
        Stream<Integer> stream2 = Stream.iterate(0, (x) -> x + 2).limit(6);
        stream2.forEach(System.out::print); // 0 2 4 6 8 10
        System.out.println("==========");
        Stream<Double> stream3 = Stream.generate(Math::random).limit(2);
        stream3.forEach(System.out::print);//随机产生两个小数
    }
}

5.1.4.使用 BufferedReader.lines() 方法,将每行内容转成流

public class Test {
    public static void main(String[] args) throws FileNotFoundException {
        BufferedReader reader = new BufferedReader(new FileReader("d:\\study\\demo\\test_stream.txt"));
        Stream<String> lineStream = reader.lines();
        lineStream.forEach(System.out::println);
    }
}

5.1.5.使用 Pattern.splitAsStream() 方法,将字符串分隔成流

public class Test {
    public static void main(String[] args) {
        Pattern pattern = Pattern.compile(",");
        Stream<String> stringStream = pattern.splitAsStream("tom,jack,jerry,john");
        stringStream.forEach(System.out::println);
    }
}

5.2.中间操作

5.2.1.筛选与切片

  • filter:过滤流中的某些元素
  • limit(n):获取n个元素
  • skip(n):跳过n元素,配合limit(n)可实现分页
  • distinct:通过流中元素的 hashCode() 和 equals() 去除重复元素
//filter 测试
public class Test {
    public static void main(String[] args) {
        List<String> list = Arrays.asList("aaa", "ff", "dddd","eeeee","hhhhhhh");

        //把字符串长度大于3的过滤掉
        Stream<String> stringStream = list.stream().filter(s -> s.length() <= 3);

        stringStream.forEach(System.out::println);

        System.out.println("===================");


        //验证整个流只遍历一次
        //stream只有遇到终止操作才会触发流启动,中间操作都是lazy
        Stream.of(1, 2, 3, 4, 5)
        .filter(i -> {
            System.out.println("filter1的元素:" + i);
            return i > 0;
        }).filter(i -> {
            System.out.println("filter2的元素:" + i);
            return i == 5;
        }).forEach(i-> System.out.println("最后结果:"+i));


    }
}
//limit 测试
public class Test {
    public static void main(String[] args) {
        List<String> list = Arrays.asList("aaa", "ff", "dddd","eeeee","hhhhhhh");

        //取三个元素
        List<String> result = list.stream().limit(3).collect(Collectors.toList());

        System.out.println(result);

    }
}
//limit 和 skip 测试
public class Test {
    public static void main(String[] args) {
        List<String> list = Arrays.asList("11", "22", "33","44","55","66","77","88","99");

        //演示skip:跳过前三条记录
        list.stream().skip(3).forEach(System.out::println);
        
        //模拟翻页,每页3条记录
        //第一页
        List<String> page1= list.stream().skip(0).limit(3).collect(Collectors.toList());
        System.out.println(page1);
        //第二页
        List<String> page2= list.stream().skip(3).limit(3).collect(Collectors.toList());
        System.out.println(page2);
        //第三页
        List<String> page3= list.stream().skip(6).limit(3).collect(Collectors.toList());
        System.out.println(page3);

        //limit和skip顺序换一下
        //可以看出,最终的结果会收到执行顺序的影响
        List<String> page4= list.stream().limit(3).skip(1).collect(Collectors.toList());
        System.out.println(page4);
    }
}

//distinct去重测试
//注意:当我们自己重写hashcode和equals的方法的时候,要遵循一个原则:
//如果两个对象的hashcode相等,那么用equals比较不一定相等;反之,如果两个对象用equals比较相等,那么他们的hashcode也一定相等
public class Student {
    private Integer id;
    private String name;

    public Student(Integer id, String name) {
        this.id = id;
        this.name = name;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        Student student = (Student) o;
        return getId().equals(student.getId()) &&
                getName().equals(student.getName());
    }

    @Override
    public int hashCode() {
        return Objects.hash(getId(), getName());
    }

    @Override
    public String toString() {
        return "Student{" +
                "id=" + id +
                ", name='" + name + '\'' +
                '}';
    }
}

//去掉重复的student
//1.Student类的hashcode和equals包含了id和name
//2.Student类的hashcode和equals中只包含name
public class Test {
    public static void main(String[] args) {
        List<Student> studentList = Arrays.asList(
               new Student(1, "zhangsan"),
                new Student(6, "zhangsan"),
                new Student(2, "lisi"),
                new Student(5, "lisi"),
                new Student(3, "wangwu"));
        //1.学生对象去重
        List<Student> result = studentList.stream().distinct().collect(Collectors.toList());
        System.out.println(result);


        //2.普通字符串去重
        Stream<String> stringStream = Stream.of("a", "a", "b", "c", "d");
        List<String> stringList = stringStream.distinct().collect(Collectors.toList());
        System.out.println(stringList);
        
    }
}

5.2.2.映射(map和flatMap)

public class Test {
    public static void main(String[] args) {

            //第一个例子对比
            List<String> list = Arrays.asList("a,b,c", "1,2,3");

            //将每个元素转成一个新的且不带逗号的元素
            //注意:这里元素是值在list中的元素,一共有两个,分别是"a,b,c" 和"1,2,3"
            //map函数传入的lambda表达式就是我们的转换逻辑,需要返回一个转换之后的元素
            Stream<String> s1 = list.stream().map(s -> s.replaceAll(",", ""));
            s1.forEach(System.out::println); // abc  123

            System.out.println("===============");
        
            List<Integer> integerList = Arrays.asList(1, 2, 3);
            integerList.stream().map(i->i*2).forEach(System.out::println);

            System.out.println("===============");
        
            //将每个元素转换成一个stream
            //注意:flatMap跟上面的map函数对比
            //两者传入的lambda都是转换逻辑,但是map中的lambda返回的是一个转换后的新元素,
            //flatMap可以把每一个元素进一步处理:例如"a,b,c"进一步分隔成a b c三个元素
            //返回的是这三个元素形成的三个stream,最终把这些单独的stream合并成一个stream返回
            //总结:可以看出,flatMap相比于map,它可以把每一个元素再进一步拆分成更多的元素,
            // 最后,拆分出来的元素个数会多于最初输入的列表中的元素个数
            //就这个例子而言,最初输入两个元素"a,b,c" 和"1,2,3",结果是6个元素  a b c 1 2 3
            Stream<String> s3 = list.stream().flatMap(s -> {

                String[] split = s.split(",");
                Stream<String> s2 = Arrays.stream(split);
                return s2;
            });
            s3.forEach(System.out::println); // a b c 1 2 3

            System.out.println("===============");

            //第二个例子(嵌套的list)[["a","b","c"],["d","e","f"],["h","k"]]
            //输出结果要求是:["A","B","C","D","E","F","G","H"]
            List<List<String>> nestedList = Arrays.asList(
                                                Arrays.asList("a","b","c"),
                                                Arrays.asList("d","e","f"),
                                                Arrays.asList("h","k")
                                            );

            Stream<String> s4 = nestedList.stream()
                .flatMap(Collection::stream)
                .map(s -> s.toUpperCase());


            s4.forEach(System.out::print);
    }
}

5.2.3.排序

  • sorted():自然排序,流中元素需实现Comparable接口
  • sorted(Comparator com):定制排序,自定义Comparator排序器
//字符串排序
public class Test {
    public static void main(String[] args) {
        List<String> list = Arrays.asList("aaa", "ff", "dddd");

        //String 类自身已实现Compareable接口,可以按照字符的自然顺序【升序】排序
        list.stream().sorted().forEach(System.out::println);// aaa dddd ff
 		System.out.println("=====");
        //给sorted函数传入一个lambda表达式
        //1.自定义排序规则,按照字符串的长度【升序】排序,也就是字符串长度最短的排在最前面
        list.stream().sorted((s1,s2)->s1.length()-s2.length()).forEach(System.out::println);//ff aaa dddd
 		System.out.println("=====");
        //2.自定义排序规则,按照字符串的长度【降序】排序,也就是字符串长度最长的排在最前面
        list.stream().sorted((s1,s2)->s2.length()-s1.length()).forEach(System.out::println);//dddd aaa ff
    }
}

//对象排序
public class Employee {
    private String name;
    private Integer salary;
    public Employee(String name,Integer salary) {
        this.name = name;
        this.salary = salary;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public Integer getSalary() {
        return salary;
    }
    public void setSalary(Integer salary) {
        this.salary = salary;
    }

    @Override
    public String toString() {
        return "Employee{" +
                "name='" + name + '\'' +
                ", salary=" + salary +
                '}';
    }
}

//测试类
public class Test {
    public static void main(String[] args) {
            List<Employee> list = Arrays.asList(
                    new Employee("Tom",1000),
                    new Employee("Jack",900),
                    new Employee("John",1300),
                    new Employee("Jack",2000)
            );
            //自定义排序规则,先按照名称【升序】,如果名称相同,再按照工资【降序】
            list.stream().sorted((e1,e2)->{
                if(e1.getName().equals(e2.getName())){
                    return e2.getSalary()-e1.getSalary();
                }else{
                    return e1.getName().compareTo(e2.getName());
                }
            }).forEach(System.out::println);

            //输出结果:
            //        Employee{name='Jack', salary=2000}
            //        Employee{name='Jack', salary=900}
            //        Employee{name='John', salary=1300}
            //        Employee{name='Tom', salary=1000}

            //打印原始列表,看看是否被改变,注意我们通过stream进行排序操作,原始的列表元素顺序没有变化,也就是说我们没有修改原始的list
            System.out.println(list);

            //Stream排序和集合本身的排序方法对比

            //我们使用List接口本身的sort方法再来排序一下看看
            list.sort((e1,e2)->{
                if(e1.getName().equals(e2.getName())){
                    return e2.getSalary()-e1.getSalary();
                }else{
                    return e1.getName().compareTo(e2.getName());
                }
            });
            //排序后再次打印一下list本身,可以发现,list本身元素的顺序被修改过了
            System.out.println(list);
        }
}

5.2.4.消费
peek:如同于map,能得到流中的每一个元素。但map接收的是一个Function表达式,有返回值;而peek接收的是Consumer表达式,没有返回值。

//为Tom增加500工资
public class Test {
    public static void main(String[] args) {
        List<Employee> list = Arrays.asList(
                new Employee("Tom",1000),
                new Employee("John",1300),
                new Employee("Jack",2000)
        );
        //如果是Tom,工资增加500
        list.stream().peek(e->{
            if("Tom".equals(e.getName())){
                e.setSalary(500+e.getSalary());
            }
        }).forEach(System.out::println);
        //输出结果
//        Employee{name='Tom', salary=1500}
//        Employee{name='John', salary=1300}
//        Employee{name='Jack', salary=2000}
    }
}

5.3.终止操作

5.3.1.匹配

public class Test {
    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(2, 1, 3, 4, 5);

        //流中所有的元素都匹配,返回true,否则返回false
        boolean allMatch = list.stream().allMatch(e -> {
            System.out.println(e);
            return e > 10;
        }); //false
        System.out.println("allMatch:"+allMatch);
        //流中没有任何的元素匹配,返回true,否则返回false
        boolean noneMatch = list.stream().noneMatch(e -> {
            System.out.println(e);
            return e > 10;
        }); //true
        System.out.println("noneMatch:"+noneMatch);
        //流中只要有任何一个元素匹配,返回true,否则返回false
        boolean anyMatch = list.stream().anyMatch(e -> {
            System.out.println(e);
            return e > 1;
        });  //true
        System.out.println("anyMatch:"+anyMatch);
        //返回流的第一个元素
        Integer findFirst = list.stream().findFirst().get(); //2
        System.out.println("findFirst"+findFirst);
        //返回流中的任意元素
        Integer findAny = list.stream().findAny().get(); //2
        System.out.println("findAny:"+findAny);
    }
}

5.3.2.聚合

public class Test {
    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(1, 2, 3, 4, 5);

        //计算元素总的数量
        long count = list.stream().count(); //5
        System.out.println(count);
        //找出最大的元素(需要传入Lambda比较器)
        Integer max = list.stream().max(Integer::compareTo).get(); //5
        System.out.println(max);
        //找出最小元素(需要传入Lambda比较器)
        Integer min = list.stream().min(Integer::compareTo).get(); //1
        System.out.println(min);
    }
}

5.3.3.归约
在java.util.stream.Stream接口中,reduce有下面三个重载的方法

/**
第一次执行时,accumulator函数的第一个参数为流中的第一个元素,第二个参数为流中元素的第二个元素;第二次执行时,第一个参数为第一次函数执行的结果,第二个参数为流中的第三个元素;依次类推。
*/
Optional<T> reduce(BinaryOperator<T> accumulator);

/**
流程跟上面一样,只是第一次执行时,accumulator函数的第一个参数为identity,而第二个参数为流中的第一个元素。
*/
T reduce(T identity, BinaryOperator<T> accumulator);

/**
在串行流(stream)中,该方法跟第二个方法一样,即第三个参数combiner不会起作用。
在并行流(parallelStream)中,我们知道流被fork join创建出多个线程进行执行,此时每个线程的执行流程就跟第二个方法reduce(identity,accumulator)一样,而第三个参数combiner函数,则是将每个线程的执行结果当成一个新的流,然后使用第一个方法reduce(accumulator)流程进行归约。
*/
<U> U reduce(U identity,
             BiFunction<U, ? super T, U> accumulator,
             BinaryOperator<U> combiner);

归约应用举例


public class Test {
    public static void main(String[] args) {

        List<Integer> list = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);

        Integer v = list.stream().reduce((a1, a2) -> a1 + a2).get();
        System.out.println("reduce计算v="+v);   // 55



        Integer v1 = list.stream().reduce(10, (a1, a2) -> a1 + a2);
        System.out.println("reduce计算v1="+v1);  //65


        Integer v2 = list.stream().reduce(0,
                (a1, a2) -> {
                    return a1 + a2;
                },
                (a1, a2) -> {
                    return 1000; //第二个表达式在串行流中无效,这里返回1000测试
                });
        System.out.println("reduce计算v2="+v2); 


        //并行流reduce传三个参数
        Integer v3 = list.parallelStream().reduce(0,
                (a1, a2) -> {
                    System.out.println(Thread.currentThread().getName()+":parallelStream accumulator: a1:" + a1 + "  a2:" + a2);
                    return a1 + a2;
                },
                (a1, a2) -> {
                    System.out.println(Thread.currentThread().getName()+":parallelStream combiner: a1:" + a1 + "  a2:" + a2);
                    return a1 + a2;
                });

        System.out.println("并行流reduce计算v3=:"+v3);
    }
}

5.3.4.收集
collect:接收一个Collector实例,将流中元素收集成另外一个数据结构

<R, A> R collect(Collector<? super T, A, R> collector);

应用举例:

//创建一个Person类
public class Person {
    private String name;
    private String sex;
    private Integer age;
    public Person(String name, String sex, Integer age) {
        this.name = name;
        this.sex = sex;
        this.age = age;
    }

    @Override
    public String toString() {
        return "Person{" +
                "name='" + name + '\'' +
                ", sex='" + sex + '\'' +
                ", age=" + age +
                '}';
    }

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getSex() {
        return sex;
    }
    public void setSex(String sex) {
        this.sex = sex;
    }
    public Integer getAge() {
        return age;
    }
    public void setAge(Integer age) {
        this.age = age;
    }
}
public class Test {


    public static void main(String[] args) {
        //1.collect(Collectors.toList()) 把流转换成一个列表(允许重复值)
        Stream<String> stringStream = Stream.of("aa","bb","dd","ee","bb");
        List<String> listResult = stringStream.collect(Collectors.toList());
        System.out.println(listResult);//[aa, bb, dd, ee, bb]

        //2.collect(Collectors.toSet()) 把流转换成一个集合(去重)
        Stream<String> stringStream1 = Stream.of("aa","bb","dd","ee","bb");
        Set<String> setResult = stringStream1.collect(Collectors.toSet());
        System.out.println(setResult);//[aa, bb, dd, ee]

        //3.collect(Collectors.toCollection(LinkedList::new)) 把流转换成一个指定的集合类型(LinkedList)
        Stream<String> stringStream2 = Stream.of("aa","bb","dd","ee","bb");
        LinkedList<String> linkedListResult = stringStream2.collect(Collectors.toCollection(LinkedList::new));
        System.out.println(linkedListResult);//[aa, bb, dd, ee, bb]

        //4.collect(Collectors.toCollection(ArrayList::new)) 把流转换成一个指定的集合类型(ArrayList)
        Stream<String> stringStream3 = Stream.of("aa","bb","dd","ee","bb");
        ArrayList<String> arrayListResult = stringStream3.collect(Collectors.toCollection(ArrayList::new));
        System.out.println(arrayListResult);//[aa, bb, dd, ee, bb]

        //5.collect(Collectors.toCollection(TreeSet::new)) 把流转换成一个指定的集合类型(TreeSet)
        Stream<String> stringStream4 = Stream.of("aa","bb","dd","ee","bb");
        TreeSet<String> treeSetResult = stringStream4.collect(Collectors.toCollection(TreeSet::new));
        System.out.println(treeSetResult);//[aa, bb, dd, ee]

        //6.collect(Collectors.joining()) 使用joining拼接流中的元素
        Stream<String> stringStream5 = Stream.of("A","B","C","D","E");
        String result5 = stringStream5.collect(Collectors.joining());
        System.out.println(result5);//ABCDE

        //7.collect(Collectors.joining("-")) 使用joining拼接流中的元素并指定分隔符
        Stream<String> stringStream6 = Stream.of("A","B","C","D","E");
        String result6 = stringStream6.collect(Collectors.joining("-"));
        System.out.println(result6);//A-B-C-D-E

        //7.collect(Collectors.joining("-","<",">")) 使用joining拼接流中的元素并指定分隔符
        Stream<String> stringStream7 = Stream.of("A","B","C","D","E");
        String result7 = stringStream7.collect(Collectors.joining("-","<",">"));
        System.out.println(result7);//<A-B-C-D-E>



        //8.collect(Collectors.groupingBy(Person::getSex) 对person流按照性别进行分组
        Stream<Person> stringStream8 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("wangwu", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("xiaoming", "女", 13)
        );

        Map<String, List<Person>> resultMap1 = stringStream8.collect(Collectors.groupingBy(Person::getSex));
        System.out.println(resultMap1.toString());//{女=[Person{name='lisi', sex='女', age=11}, Person{name='xiaoming', sex='女', age=13}], 男=[Person{name='zhangsan', sex='男', age=10}, Person{name='wangwu', sex='男', age=15}, Person{name='zhaoliu', sex='男', age=12}]}

        //9.collect(Collectors.groupingBy(Person::getSex, Collectors.mapping(Person::getName, Collectors.toList())))
        // 对person流按照性别进行分组,并且把每一组对象流中人员的姓名转成列表
        Stream<Person> stringStream9 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("wangwu", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("xiaoming", "女", 13)
        );
        Map<String, List<String>> listMap = stringStream9.collect(
                Collectors.groupingBy(Person::getSex, Collectors.mapping(Person::getName, Collectors.toList()))
        );
        System.out.println(listMap.toString());//{女=[lisi, xiaoming], 男=[zhangsan, wangwu, zhaoliu]}

        //10.collect(Collectors.groupingBy(Person::getSex, Collectors.mapping(Person::getAge, Collectors.maxBy(Integer::compareTo))))
        // 对person流按照性别进行分组,并统计每一组中年龄最大的人的年龄
        Stream<Person> stringStream10 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("wangwu", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("xiaoming", "女", 13)
        );
        Map<String, Optional<Integer>> listMap1 = stringStream10.collect(
                Collectors.groupingBy(Person::getSex, Collectors.mapping(Person::getAge, Collectors.maxBy(Integer::compareTo)))
        );
        System.out.println(listMap1.toString());//{女=Optional[13], 男=Optional[15]}


        //11.collect(
        //           Collectors.groupingBy(Person::getName,
        //                                 Collectors.reducing(BinaryOperator.maxBy(Comparator.comparingInt(Person::getAge)))
        //   )
        //对person流按照性别进行分组,并统计每一组中年龄最大的人
        //这个案例使用了groupingBy和reducing组合
        Stream<Person> stringStream111 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("zhangsan", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("lisi", "女", 13)
        );
        Map<String, Optional<Person>> resultMap111 = stringStream111.collect(
                Collectors.groupingBy(Person::getSex,
                        Collectors.reducing(BinaryOperator.maxBy(Comparator.comparingInt(Person::getAge)))
                )
        );
        System.out.println(resultMap111.toString());//{女=Optional[Person{name='lisi', sex='女', age=13}], 男=Optional[Person{name='zhangsan', sex='男', age=15}]}


        //12.collect(Collectors.groupingBy(Person::getSex,
        //                 Collectors.reducing(0,Person::getAge,(x,y)->x+y)
        //          )
        //        )
        //对person流按照性别进行分组,并统计每一组人员年龄和
        Stream<Person> stringStream121 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("zhangsan", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("lisi", "女", 13)
        );
        Map<String, Integer> resultMap121 = stringStream121.collect(
                Collectors.groupingBy(Person::getSex,
                        Collectors.reducing(0,Person::getAge,(x,y)->x+y)
                )
        );
        /*上面这段如果不使用reducing,还可以用下面这中方式完成
        Map<String, Integer> resultMap121 = stringStream121.collect(
                             Collectors.groupingBy(Person::getSex, Collectors.summingInt(Person::getAge))
        );*/
        System.out.println(resultMap121.toString());//{女=24, 男=37}



        //12.collect(Collectors.groupingBy(Person::getName,  TreeMap::new, Collectors.toList()))
        // 对person流按照name进行分组,结果转成TreeMap,key是name,value是这个组的对象列表
        //groupingBy的第一个参数就是获取分组的属性,第二个参数指定返回类型,第三个是把每个分组里面的对象元素转成一个列表
        Stream<Person> stringStream11 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("lisi", "女", 11),
                new Person("zhangsan", "男", 15),
                new Person("lisi", "男", 12),
                new Person("xiaoming", "女", 13)
        );
        TreeMap<String, List<Person>> listMap2 = stringStream11.collect(
                Collectors.groupingBy(Person::getName,  TreeMap::new, Collectors.toList())
        );
        System.out.println(listMap2.toString());//{lisi=[Person{name='lisi', sex='女', age=11}, Person{name='lisi', sex='男', age=12}], xiaoming=[Person{name='xiaoming', sex='女', age=13}], zhangsan=[Person{name='zhangsan', sex='男', age=10}, Person{name='zhangsan', sex='男', age=15}]}


        //13.collect(Collectors.collectingAndThen(
        //                Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(Person::getName))),
        //                ArrayList::new))
        //对Person流先通过TreeSet去重,去重的比较属性是name,然后在把这个TreeSet中的元素转换成ArrayList
        Stream<Person> stringStream12 = Stream.of(
                new Person("lisi", "女", 11),
                new Person("lisi", "女", 11),
                new Person("zhangsan", "男", 15),
                new Person("zhangsan", "男", 15),
                new Person("xiaoming", "女", 13)
        );

        List<Person> list = stringStream12.collect(Collectors.collectingAndThen(
                Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(Person::getName))),
                ArrayList::new));//这里的ArrayList::new等同于pset->new ArrayList(pset),是把前面生成的TreeSet赋值给ArrayList构造函数
        System.out.println(list);//[Person{name='lisi', sex='女', age=11}, Person{name='xiaoming', sex='女', age=13}, Person{name='zhangsan', sex='男', age=15}]


        //14.collect(Collectors.groupingBy(Person::getName, Collectors.summingInt(Person::getAge)))
        // 对person流按照姓名进行分组,并对每一个组内的人员的年龄求和
        Stream<Person> stringStream13 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("zhangsan", "女", 11),
                new Person("lisi", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("lisi", "女", 13)
        );

        Map<String, Integer> resultMap2 = stringStream13.collect(Collectors.groupingBy(Person::getName, Collectors.summingInt(Person::getAge)));
        System.out.println(resultMap2.toString());//{lisi=28, zhaoliu=12, zhangsan=21}

        //15.collect(Collectors.groupingBy(Person::getName, Collectors.averagingInt(Person::getAge)))
        // 对person流按照姓名进行分组,并对每一个组内的人员的年龄求平均值
        Stream<Person> stringStream14 = Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("zhangsan", "女", 11),
                new Person("lisi", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("lisi", "女", 13)
        );

        Map<String, Double> resultMap3 = stringStream14.collect(Collectors.groupingBy(Person::getName, Collectors.averagingInt(Person::getAge)));
        System.out.println(resultMap3.toString());//{lisi=14.0, zhaoliu=12.0, zhangsan=10.5}

        //16.parallel().collect(
        //                Collectors.groupingByConcurrent(Person::getSex, Collectors.summingInt(Person::getAge))
        //        )
        //使用并行流,把人员按照性别分组,计算每一组中的年龄和,返回的类型是ConcurrentMap,保证线程安全
        Stream<Person> stringStream16 =  Stream.of(
                new Person("zhangsan", "男", 10),
                new Person("zhangsan", "女", 11),
                new Person("lisi", "男", 15),
                new Person("zhaoliu", "男", 12),
                new Person("zhaoliu", "男", 16),
                new Person("zhaoliu", "男", 17),
                new Person("lisi", "女", 13));
        ConcurrentMap<String, Integer> resultMap4 = stringStream16.parallel().collect(
                Collectors.groupingByConcurrent(Person::getSex, Collectors.summingInt(Person::getAge))
        );
        System.out.println(resultMap4.toString());//{女=24, 男=70}

        //17.collect(Collectors.partitioningBy(p -> p.getAge() > 12))
        //把流中元素根据年龄是否大于12分成两组,保存在Map中,key是true或者false,value是对象列表
        Stream<Person> stringStream17 =  Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("wangwu", "男", 10),
                new Person("lisi", "男", 15),
                new Person("zhaoliu", "女", 13));
        Map<Boolean, List<Person>> resultMap5 = stringStream17.collect(Collectors.partitioningBy(p -> p.getAge() > 12));
        System.out.println(resultMap5.toString());//{false=[Person{name='zhangsan', sex='女', age=11}], true=[Person{name='lisi', sex='男', age=15}, Person{name='lisi', sex='女', age=13}]}

        //18.collect(Collectors.partitioningBy(p -> p.getAge() > 12,Collectors.summingInt(Person::getAge)))
        //把流中元素根据年龄是否大于12分成两组,保存在Map中,key是true或者false,每一组的年龄的和
        Stream<Person> stringStream18 =  Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("wangwu", "男", 10),
                new Person("lisi", "男", 15),
                new Person("zhaoliu", "女", 13));
        Map<Boolean, Integer> resultMap6 = stringStream18.collect(Collectors.partitioningBy(p -> p.getAge() > 12,Collectors.summingInt(Person::getAge)));
        System.out.println(resultMap6.toString());//{false=21, true=28}

        //19.Collectors.toMap:有两个参数的toMap方法,流中对象的key是不允许存在相同的,否则报错
        //toMap的第二个参数需要创建一个列表,并且key对应的元素对象放入列表
        Stream<Person> stringStream19 =  Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("zhaoliu", "女", 13));
        Map<String, List<Person>> resultMap7 = stringStream19.collect(Collectors.toMap(Person::getName, p -> {
            List<Person> personList = new ArrayList<>();
            personList.add(p);
            return personList;
        }));
        System.out.println(resultMap7.toString());//{zhaoliu=[Person{name='zhaoliu', sex='女', age=13}], zhangsan=[Person{name='zhangsan', sex='女', age=11}]}

        //20.Collectors.toMap:有两个参数的toMap方法,流中对象的key是不允许存在相同的,否则报错
        //toMap的第二个参数直接使用流中的对象作为key所对应的value
        Stream<Person> stringStream20 = Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("zhaoliu", "女", 13));
        Map<String, Person> resultMap8 = stringStream20.collect(Collectors.toMap(Person::getName, p -> p));
        System.out.println(resultMap8.toString());//{zhaoliu=Person{name='zhaoliu', sex='女', age=13}, zhangsan=Person{name='zhangsan', sex='女', age=11}}


        //21.Collectors.toMap:有三个参数的toMap方法,流中对象的key是允许存在相同的,
        // 第三个参数表示key重复的处理方式(这里是把重复的key对应的value用新的替换老的)
        //toMap的第二个参数直接使用流中的对象作为key所对应的value
        Stream<Person> stringStream21 = Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("zhangsan", "男", 12),
                new Person("zhaoliu", "男", 13)
        );

        Map<String, Person> resultMap9 = stringStream21.collect(
                Collectors.toMap(Person::getName,
                        p -> p,
                        (oldPerson,newPerson)->newPerson
                )
        );
        System.out.println(resultMap9.toString());//{zhaoliu=[Person{name='zhaoliu', sex='男', age=13}], zhangsan=[Person{name='zhangsan', sex='女', age=11}, Person{name='zhangsan', sex='女', age=11}]}


        //22.Collectors.toMap:有三个参数的toMap方法,流中对象的key是允许存在相同的,第三个参数表示key重复的处理方式(这里是把重复的key对应的value放入列表)
        //toMap的第二个参数直接使用流中的对象作为key所对应的value
        Stream<Person> stringStream22 = Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("zhangsan", "女", 11),
                new Person("zhaoliu", "男", 13)
        );

        Map<String, List<Person>> resultMap10 = stringStream22.collect(
                Collectors.toMap(Person::getName,
                        p -> {
                            List<Person> personList = new ArrayList<>();
                            personList.add(p);
                            return personList;
                        },
                        (oldList,newList)->{
                            oldList.addAll(newList);
                            return oldList;
                        })
        );
        System.out.println(resultMap10.toString());//{zhaoliu=[Person{name='zhaoliu', sex='男', age=13}], zhangsan=[Person{name='zhangsan', sex='女', age=11}, Person{name='zhangsan', sex='女', age=11}]}


        //23.Collectors.toMap:有四个参数的toMap方法,流中对象的key是允许存在相同的,
        //toMap的第二个参数直接使用流中的对象作为key所对应的value
        //第三个参数表示key重复的处理方式(这里是把重复的key对应的value放入列表)
        //第四个参数可以指定一个返回的Map具体类型
        Stream<Person> stringStream23 = Stream.of(
                new Person("zhangsan", "女", 11),
                new Person("zhangsan", "女", 11),
                new Person("zhaoliu", "男", 13)
        );

        Map<String, List<Person>> resultMap11 = stringStream23.collect(
                Collectors.toMap(Person::getName,
                        p -> {
                            List<Person> personList = new ArrayList<>();
                            personList.add(p);
                            return personList;
                        },
                        (oldList,newList)->{
                            oldList.addAll(newList);
                            return oldList;
                        },
                        LinkedHashMap::new
                )

        );
        System.out.println(resultMap11.toString());//{zhangsan=[Person{name='zhangsan', sex='女', age=11}, Person{name='zhangsan', sex='女', age=11}], zhaoliu=[Person{name='zhaoliu', sex='男', age=13}]}


        //24.Collectors.summarizingInt((a -> a.getAge()))
        //针对Integer类型的元素进行汇总计算
        //得到1、元素数量 2、元素的和 3、元素的最大值 4、元素的最小值 5、平均值
        Stream<Person> personStream24=Stream.of(
                        new Person("zhangsan", "女", 11),
                        new Person("zhangsan", "女", 25),
                        new Person("zhaoliu", "男", 13)
        );
        IntSummaryStatistics intSummaryStatistics = personStream24.collect(Collectors.summarizingInt((a -> a.getAge())));
        System.out.println(intSummaryStatistics);//IntSummaryStatistics{count=3, sum=49, min=11, average=16.333333, max=25}
    }
}

image-20220617094840170

posted @ 2022-07-08 15:41  [奋斗]  阅读(360)  评论(0编辑  收藏  举报