2013年2月6日

UVA 11991 - Easy Problem from Rujia Liu?

摘要: //Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) :: Chapter 1. Algorithm Design :: General Problem Solving Techniques :: Examples//UVA 11991 - Easy Problem from Rujia Liu? // 昨晚/*题意:给n个数,m个询问,问第k个位置的v的序号是多少?思路:第一次提交 O(n)时间 ,运行错误runtime error,二维数组又爆,参考他人使用map容器和vector的//m 阅读全文

posted @ 2013-02-06 16:06 ACM_Someone like you 阅读(400) 评论(0) 推荐(0) 编辑

UVA 11995 - I Can Guess the Data Structure!

摘要: Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) :: Chapter 3. Data Structures :: Fundamental Data Structures :: Examples//11995 - I Can Guess the Data Structure!/*题意:给出输入输出数据判断是那种数据结构 一种都没有 impossible 可能是两三种 not ture 只一种 栈 队列 优先队列*///AC关键 :使用bool 函数 ----三个函数何时判断为fales#inc 阅读全文

posted @ 2013-02-06 15:19 ACM_Someone like you 阅读(299) 评论(0) 推荐(0) 编辑

UVA 10970 - Big Chocolate

摘要: Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) ::/*UVA 10970 - Big Chocolate题意:计算将一块n*m的巧克力切成n*m块所需的次数方法:我们可以先横切,先切成n条,一共切了n-1刀,然后将每条都切m-1次,则一共切了 n - 1 + n*( m - 1) = n *m - 1刀 条件要点:巧克力不能折叠,而且切开后不能把几条放一块一起切*///AC#include<stdio.h>int main(){ int m,n; while(scanf(&qu 阅读全文

posted @ 2013-02-06 15:15 ACM_Someone like you 阅读(161) 评论(0) 推荐(0) 编辑

11729 Commando War

摘要: Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) :: Chapter 1. Algorithm Design :: General Problem Solving Techniques :: Examples//11729 Commando War/*题意:n个部下,每个部下需要Bi分钟交待任务,让后Ji分钟后完成任务。确定一个顺序,使得最早完成任务。把 说明时间每次累加求和 每组说明和作业时间和 比较大小即可 贪心*///AC#include<stdio.h>#include& 阅读全文

posted @ 2013-02-06 15:12 ACM_Someone like you 阅读(613) 评论(0) 推荐(0) 编辑

UVA 11997 - K Smallest Sums

摘要: Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) :: Chapter 3. Data Structures :: Fundamental Data Structures :: Examples 阅读全文

posted @ 2013-02-06 15:04 ACM_Someone like you 阅读(439) 评论(0) 推荐(0) 编辑

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