Oracle拆分字符串,字符串分割的函数。

第一种:oracle字符串分割和提取

分割

create or replace function Get_StrArrayLength
(
  av_str varchar2,  --要分割的字符串
  av_split varchar2  --分隔符号
)
return number
is
  lv_str varchar2(1000);
  lv_length number;
begin
  lv_str:=ltrim(rtrim(av_str));
  lv_length:=0;
  while instr(lv_str,av_split)<>0 loop
     lv_length:=lv_length+1;
     lv_str:=substr(lv_str,instr(lv_str,av_split)+length(av_split),length(lv_str));
  end loop;
  lv_length:=lv_length+1;
  return lv_length;
end Get_StrArrayLength;

 

提取

 

create or replace function Get_StrArrayStrOfIndex
(
  av_str varchar2,  --要分割的字符串
  av_split varchar2,  --分隔符号
  av_index number --取第几个元素
)
return varchar2
is
  lv_str varchar2(1024);
  lv_strOfIndex varchar2(1024);
  lv_length number;
begin
  lv_str:=ltrim(rtrim(av_str));
  lv_str:=concat(lv_str,av_split);
  lv_length:=av_index;
  if lv_length=0 then
      lv_strOfIndex:=substr(lv_str,1,instr(lv_str,av_split)-length(av_split));
  else
      lv_length:=av_index+1;
     lv_strOfIndex:=substr(lv_str,instr(lv_str,av_split,1,av_index)+length(av_split),instr(lv_str,av_split,1,lv_length)-instr(lv_str,av_split,1,av_index)-length(av_split));
  end if;
  return  lv_strOfIndex;
end Get_StrArrayStrOfIndex;

测试:   select Get_StrArrayStrOfIndex('songguojun$@111111537','$',0) from dual 

结果:


 

第二种:

本函数可以将“目标字符串”以“指定字符串”进行拆分,并通过表结构返回结果。代码如下:

CREATE OR REPLACE TYPE str_split IS TABLE OF VARCHAR2 (4000);
CREATE OR REPLACE FUNCTION splitstr(p_string IN VARCHAR2, p_delimiter IN VARCHAR2)
    RETURN str_split 
    PIPELINED
AS
    v_length   NUMBER := LENGTH(p_string);
    v_start    NUMBER := 1;
    v_index    NUMBER;
BEGIN
    WHILE(v_start <= v_length)
    LOOP
        v_index := INSTR(p_string, p_delimiter, v_start);

        IF v_index = 0
        THEN
            PIPE ROW(SUBSTR(p_string, v_start));
            v_start := v_length + 1;
        ELSE
            PIPE ROW(SUBSTR(p_string, v_start, v_index - v_start));
            v_start := v_index + 1;
        END IF;
    END LOOP;

    RETURN;
END splitstr;

创建完毕后,我们来测试一下,例如执行如下SQL:

select * from table(splitstr('Hello,Cnblogs!',','));

其输出结果为一个两行的表,如下图:

2009-9-9-11.38.15

将行转为列显示:

select a.column_value v1,b.column_value v2 from 
(select * from (select rownum rn,t.* from table(splitstr('Hello,Cnblogs!',',')) t)) a,
(select * from (select rownum rn,t.* from table(splitstr('Hello,Cnblogs!',',')) t)) b
where a.rn=1 and b.rn=2

如图:

2009-9-9-11.44.53

posted on 2012-12-13 15:26  小东北  阅读(64666)  评论(3编辑  收藏  举报