246. 区间最大公约数
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; typedef long long LL; const int N = 500010; int n, m; LL w[N]; struct Node { int l, r; LL sum, d; }tr[N * 4]; LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; } void pushup(Node &u, Node &l, Node &r) { u.sum = l.sum + r.sum; u.d = gcd(l.d, r.d); } void pushup(int u) { pushup(tr[u], tr[u << 1], tr[u << 1 | 1]); } void build(int u, int l, int r) { if (l == r) { LL b = w[r] - w[r - 1]; tr[u] = {l, r, b, b}; } else { tr[u].l = l, tr[u].r = r; int mid = l + r >> 1; build(u << 1, l, mid), build(u << 1 | 1, mid + 1, r); pushup(u); } } void modify(int u, int x, LL v) { if (tr[u].l == x && tr[u].r == x) { LL b = tr[u].sum + v; tr[u] = {x, x, b, b}; } else { int mid = tr[u].l + tr[u].r >> 1; if (x <= mid) modify(u << 1, x, v); else modify(u << 1 | 1, x, v); pushup(u); } } Node query(int u, int l, int r) { if (tr[u].l >= l && tr[u].r <= r) return tr[u]; else { int mid = tr[u].l + tr[u].r >> 1; if (r <= mid) return query(u << 1, l, r); else if (l > mid) return query(u << 1 | 1, l, r); else { auto left = query(u << 1, l, r); auto right = query(u << 1 | 1, l, r); Node res; pushup(res, left, right); return res; } } } int main() { scanf("%d%d", &n, &m); for (int i = 1; i <= n; i ++ ) scanf("%lld", &w[i]); build(1, 1, n); int l, r; LL d; char op[2]; while (m -- ) { scanf("%s%d%d", op, &l, &r); if (*op == 'Q') { auto left = query(1, 1, l); Node right({0, 0, 0, 0}); if (l + 1 <= r) right = query(1, l + 1, r); printf("%lld\n", abs(gcd(left.sum, right.d))); } else { scanf("%lld", &d); modify(1, l, d); if (r + 1 <= n) modify(1, r + 1, -d); } } return 0; }
注意query里面要取绝对值,因为题目中可能会出现负数。