NYOJ--2--括号配对问题
1 /* 2 Name: NYOJ--2--括号配对问题 3 Author: shen_渊 4 Date: 18/04/17 21:15 5 Description: 先入栈个‘#’ 就好做了 6 */ 7 #include<bits/stdc++.h> 8 using namespace std; 9 bool cmp(char,char) ; 10 int main(){ 11 int n;cin>>n; 12 while(n--){ 13 string str;cin>>str; 14 stack<char> s; 15 while(!s.empty())s.pop(); 16 s.push('#');// 17 for(int i=0; i<str.size(); ++i){ 18 if(str[i]=='[' || str[i]=='(') 19 s.push(str[i]); 20 else if((str[i]==']' &&s.top()=='[') || (str[i]==')' && s.top()=='(')) 21 s.pop(); 22 else 23 s.push(str[i]); 24 } 25 if(s.top() != '#')cout<<"No"<<endl; 26 else cout<<"Yes"<<endl; 27 while(s.top() != '#')s.pop(); 28 } 29 return 0; 30 } 31 bool cmp(char c,char cc){ 32 if(c == '(' && cc == ')')return 1; 33 else if(c == '[' && cc == ']')return 1; 34 else return 0; 35 } 36 /* 37 仔细一想,于是…… 38 */ 39 #include<bits/stdc++.h> 40 using namespace std; 41 bool cmp(char,char) ; 42 int main(){ 43 int n;cin>>n; 44 while(n--){ 45 string str;cin>>str; 46 int a = 0,b = -1,pos; 47 while(a != b){ 48 a = str.size(); 49 while((pos = str.find("()")) != string::npos)str.erase(pos,2); 50 while((pos = str.find("[]")) != string::npos)str.erase(pos,2); 51 b = str.size(); 52 } 53 if(str == "")cout<<"Yes"<<endl; 54 else cout<<"No"<<endl; 55 } 56 return 0; 57 }