[LeetCode]Remove Duplicates from Sorted List

题目描述:(链接

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

解题思路:

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode* deleteDuplicates(ListNode* head) {
12         ListNode *prev = NULL;
13         for (ListNode *cur = head; cur != NULL; cur = cur->next) {
14             if (cur == head) {
15                 prev = cur;
16                 continue;
17             }
18             
19             if (cur->val == prev->val) {
20                 prev->next = cur->next;
21             } else {
22                 prev = cur;
23             }
24         }
25         
26         return head;
27     }
28 };

 递归版:2015-10-26更新

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode* deleteDuplicates(ListNode* head) {
12         if (!head || !(head->next)) return head;
13         
14         ListNode *p = head->next;
15         if (p->val == head->val) {
16             while (p && p->val == head->val) {
17                 ListNode *tmp = p;
18                 p = p->next;
19                 delete tmp;
20             }
21             head->next = p;
22             return deleteDuplicates(head);
23         } else {
24             head->next = deleteDuplicates(p);
25             return head;
26         }
27     }
28 };

 

posted @ 2015-10-22 23:19  skycore  阅读(120)  评论(0编辑  收藏  举报