[LeetCode]Single Number

题目描述：

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

解题方案：

该题利用异或可以方便求解，下面本题是代码：

class Solution {
public:
    int singleNumber(int A[], int n) {
        int result = A[0];
        for(int i = 1; i < n; ++i){
            //利用异或
            result = result ^ A[i];
        }
        return result;
    }
};