摘要:
--1.查看碎片 SELECT DB_NAME() AS DatbaseName , SCHEMA_NAME(o.Schema_ID) AS SchemaName , OBJECT_NAME(s.[object_id]) AS TableName , i.name AS IndexName , RO 阅读全文
posted @ 2021-06-16 13:20 sky410 阅读(324) 评论(0) 推荐(0) 编辑
摘要:
--1.查看碎片 SELECT DB_NAME() AS DatbaseName , SCHEMA_NAME(o.Schema_ID) AS SchemaName , OBJECT_NAME(s.[object_id]) AS TableName , i.name AS IndexName , RO 阅读全文
posted @ 2021-06-16 13:20 sky410 阅读(324) 评论(0) 推荐(0) 编辑 |
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