jq判断是否点击返回，回到上一页

<script>
      window.addEventListener('pageshow', function (event) {
           if(event.persisted || window.performance && window.performance.navigation.type == 2){        // 返回2则是点击返回
               console.log('window.performance.navigation.type: '+ window.performance.navigation.type)
               // location.refresh();   //此处可以写你的实际应用的代码
           }
       },false);
</script>