Request.InputStream

将数据作为XML数据发送,例如:

public void PostXml(string url, string xml)

   
byte[] bytes = Encoding.UTF8.GetBytes(xml); 
   HttpWebRequest request 
= (HttpWebRequest) WebRequest.Create(url); 
   request.Method 
= "POST"
   request.ContentLength 
= bytes.Length; 
   request.ContentType 
= "text/xml"
   
using (Stream requestStream = request.GetRequestStream()) 
     requestStream.Write(bytes, 
0, bytes.Length); 
   }
 

   HttpWebResponse response 
= (HttpWebResponse) request.GetResponse(); 
   
if (response.StatusCode != HttpStatusCode.OK) 
     
string message = String.Format("POST failed. Received HTTP {0}"
     response.StatusCode); 
     
throw new ApplicationException(message); 
   }
 
}


接收端通过Request.InputStream读取:

byte[] byts = new byte[Request.InputStream.Length];
Request.InputStream.Read(byts,
0,byts.Length);
string req = System.Text.Encoding.Default.GetString(byts);
req 
= Server.UrlDecode(req);


对于完整的XML数据,可以:

xmlDoc = new XmlDocument();
xmlDoc.load(Request.InputStream);

 

posted @ 2008-12-25 22:40  s80895304  阅读(2035)  评论(0编辑  收藏  举报