摘要: function initFileUpload(id) { var file = $("#" + id + ""); var files = file[0].files; var formData = new FormData(); for (var i = 0; i < files.length; 阅读全文
posted @ 2019-11-06 17:25 韩梦芫 阅读(874) 评论(0) 推荐(0) 编辑