C# 打开 txt文件内容 与保存内容到 txt文件

OpenFileDialog ofd = new OpenFileDialog();
ofd.Title = "请选择要打开的文本文件";
ofd.InitialDirectory = @"C:\Users\SpringRain\Desktop";
ofd.Multiselect = true;
ofd.Filter = "文本文件|*.txt|所有文件|*.*";
ofd.ShowDialog();

//获得用户选中的文件的路径
string path = ofd.FileName;
//将文件的全路径存储到泛型集合中
list.Add(path);
//获得了用户打开文件的文件名
string fileName = Path.GetFileName(path);
//将文件名放到ListBox中
listBox1.Items.Add(fileName);
if (path == "")
{
return;
}
using (FileStream fsRead = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Read))
{
byte[] buffer = new byte[1024 * 1024 * 5];
int r = fsRead.Read(buffer, 0, buffer.Length);
textBox1.Text = Encoding.Default.GetString(buffer, 0, r);
}

 

SaveFileDialog sfd = new SaveFileDialog();
sfd.InitialDirectory = @"C:\Users\SpringRain\Desktop";
sfd.Title = "请选择要保存的文件路径";
sfd.Filter = "文本文件|*.txt|所有文件|*.*";
sfd.ShowDialog();

//获得用户要保存的文件的路径
string path = sfd.FileName;
if (path == "")
{
return;
}
using (FileStream fsWrite = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write))
{
byte[] buffer = Encoding.Default.GetBytes(textBox1.Text);
fsWrite.Write(buffer, 0, buffer.Length);
}
MessageBox.Show("保存成功");

 

 

//要获得双击的文件所对应的全路径
string path = list[listBox1.SelectedIndex];
using (FileStream fsRead = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Read))
{
byte[] buffer = new byte[1024 * 1024 * 5];
int r = fsRead.Read(buffer, 0, buffer.Length);

textBox1.Text = Encoding.Default.GetString(buffer, 0, r);
}

posted @ 2017-08-07 10:00  司元朔  阅读(11881)  评论(0编辑  收藏  举报